The line segment joining A(-7, 2) and B(3, -8) is divided by the x-axis in the ratio :
- (a)1 : 4
- (b)3 : 7
- (c)4 : 1
- (d)7 : 3
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Given,
AB is divided by the x-axis, thus y-coordinate = 0 at point of division.
A(-7, 2) and B(3, -8)
Let ratio be m : n.
By section-formula,
y = $\frac{my_2 + ny_1}{m + n}$
Substituting values we get :
⇒ 0 = $\frac{m \times (-8) + n \times (2)}{m + n}$
⇒ 0 = -8m + 2n
⇒ 8m = 2n
⇒ $\frac{m}{n} = \frac{2}{8}$
⇒ $\frac{m}{n} = \frac{1}{4}$
⇒ m : n = 1 : 4.
Hence, option 1 is the correct option.