Mr. Rahul deposited ₹ 11,700 in a recurring deposit account for 1 $\frac{1}{2}$ years. The amount deposited by him per month is :

ICSE Class 10 Mathematics PYQ · 2025 Improvement · Section A

1(xv)1 Mark · 2025 · Section A · 2025 Improvement

Mr. Rahul deposited ₹ 11,700 in a recurring deposit account for 1 $\frac{1}{2}$ years. The amount deposited by him per month is :

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Given,

Time = $1\frac{1}{2}$ years = 18 months

Amount deposited = ₹ 11,700

Amount deposited per month

= $\frac{\text{Total amount deposited}}{\text{Total number of months}}$

= $\frac{11700}{18}$

= ₹ 650.

Hence, option 1 is the correct option.

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