State the number of elements in Period 1, Period 2, and Period 3 of the Periodic Table.
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Period 1 — 2 Elements
Period 2 — 8 Elements
Period 3 — 8 Elements
ICSE Class 9 Chemistry · Solutions for Class 9 Viraf J Dalal Simplified ICSE Chemistry · 42 solved questions
State the number of elements in Period 1, Period 2, and Period 3 of the Periodic Table.
Period 1 — 2 Elements
Period 2 — 8 Elements
Period 3 — 8 Elements
Name the elements in Period 1.
Hydrogen [H] and Helium [He].
State the common feature of the electronic configuration of the elements at the end of Period 2 and Period 3 ?
The number of valence shell electrons in the elements at the end of Period 2 and Period 3 is 8.
Supply the missing word from those in brackets: If an element has one electron in it's outermost energy level [shell] then it is likely to be ............... [metallic / non- metallic].
If an element has one electron in it's outermost energy level [shell] then it is likely to be metallic.
Copy and complete the following sentences choosing the correct word or words from those given in brackets at the end of each sentence :
The similarities in the properties of a group of elements is because they have the same ............... [electronic configurations, number of outer electrons, atomic numbers.]
The similarities in the properties of a group of elements is because they have the same number of outer electrons.
What is meant by a Group in the Periodic Table.
The 18 vertical columns in the periodic table are called groups. Elements in the same group have the same number of valence electrons and similar chemical properties.
If an element is in Group 17 [or Group 7A] is it likely to be metallic or non-metallic. Give reasons.
It will be non-metallic because being in Group 17 [or Group 7A], it has 7 valence electrons. Thus, its electronegativity is high and it has a tendency to accept electrons.
Name or state the following with reference to the elements of the first three periods of the periodic table.
(a) The noble gas having duplet arrangement of electrons.
(b) The noble gas having an electronic configuration 2, 8, 8.
(c) A metalloid in period 2 and in period 3.
(d) The number of electron shells in elements of period 1, period 2 and period 3.
(e) The valency of elements in group 1 [IA].
(f) The group whose elements have zero valency.
(g) An alkaline earth metal in period 3.
(h) The non-metallic element present in period 3 other than sulphur and chlorine.
(i) A non-metal in period 2 having electronic configuration 2, 6.
(j) An electrovalent compound formed between an alkali metal and a halogen.
(k) A covalent compound formed between an element in period 1 and a halogen.
(l) An alkali metal in period 3 which dissolves in water giving a strong alkali.
(m) A metal in period 3 having valency 3.
(n) The bridge elements of period 3 of group 1 [IA], 2 [IIA] and 13 [IIIA].
(o) The periods which contain the inner transition elements.
(p) The formula of the hydroxide of the element having electronic configuration 2, 8, 2.
(q) The valency of the element in period 3 having atomic number 17.
(r) A non-metal in period 2 which is tetravalent.
(a) The noble gas having duplet arrangement of electrons — Helium
(b) The noble gas having an electronic configuration 2, 8, 8 — Argon
(c) A metalloid in period 2 and in period 3 — Metalloid in period 2 is B (Boron) and in period 3 is Si (Silicon)
(d) The number of electron shells in elements of period 1, period 2 and period 3 — Period 1 — 1 shell, Period 2 — 2 shells, Period 3 — 3 shells
(e) The valency of elements in group 1 [IA] — +1
(f) The group whose elements have zero valency — Group 18 or 0 group
(g) An alkaline earth metal in period 3 — Magnesium [Mg]
(h) The non-metallic element present in period 3 other than sulphur and chlorine — Phosphorus [P]
(i) A non-metal in period 2 having electronic configuration 2, 6 — Oxygen [O]
(j) An electrovalent compound formed between an alkali metal and a halogen — Sodium chloride [NaCl]
(k) A covalent compound formed between an element in period 1 and a halogen — Hydrogen chloride [HCl]
(l) An alkali metal in period 3 which dissolves in water giving a strong alkali — Alkali metal is Na and it dissolves in water to give strong alkali - NaOH
(m) A metal in period 3 having valency 3 — Aluminium [Al]
(n) The bridge elements of period 3 of group 1 [IA], 2 [IIA] and 13 [IIIA] — Li & Mg, Be & Al, B & Si
(o) The periods which contain the inner transition elements — Period 6 and 7
(p) The formula of the hydroxide of the element having electronic configuration 2, 8, 2 —
Since valency of element X is 2+ and valency of OH is 1-
Formula of the compound:
$$\begin{aligned}\text{X}^{2+} \phantom{\nearrow} \text{OH}^{1-} \\[0.5em] \overset{\phantom{2}{2}}{\text{X}} \space {\searrow}\mathllap{\swarrow} \space \overset{1}{\text{OH}} \Rightarrow \underset{\phantom{1}{1}}{\text{X}} \space {\searrow}\mathllap{\swarrow} \space \underset{2}{\text{OH}} \\[0.5em]\end{aligned}$$
So, we get the formula as $\bold{X(OH)}\bold{_2}$
As the element with electronic configuration 2,8,2 is Mg, Hence the compound is Mg(OH)2
(q) The valency of the element in period 3 having atomic number 17 — -1
(r) A non-metal in period 2 which is tetravalent — Carbon [C]
Give a reason why elements need to be properly classified.
An element is the basic unit of matter. They are pure substances made up of one kind of atoms and cannot be broken down into simpler substances.
Elements need to be properly classified and the best classification is the one which puts together those elements which show maximum resemblance and separates the others.
State why the basis of classification by early chemists was discarded for future classification of elements.
The method of classification was discarded by early chemists since the elements behave both as metals and non-metals, show metallic and non-metallic nature and have variable valency.
State what was Dobereiner's basis of classification of elements. State Dobereiner's Law of Triads with suitable examples.
Dobereiner arranged elements in increasing order of atomic weights - in groups of three called 'triads'.
Dobereiner's Law of Triads — Chemically analogous elements arranged in increasing order of their atomic weights formed well marked groups of three called 'triads' in which the atomic weight of the middle element was found to be generally the average [arithmetic mean] of the atomic weights of the other two elements.
Examples :
| Elements | Lithium | Sodium | Potassium |
|---|---|---|---|
| Atomic weight | 7.0 | 23.0 | 39.0 |
Atomic weight of sodium is the average (arithmetic mean) of Lithium and Potassium.
Give a reason why Dobereiner's method of classification of elements did not hold much weightage for future classification.
Dobereiner's method of classification of elements did not hold much weightage for future classification because —
State the basis of classification proposed by Newland. State Newland's Law of Octaves with a suitable example.
Newland arranged elements in increasing order of atomic weights in series of eight.
Newland's Law of Octaves — Elements when arranged in increasing order of their atomic weights show resemblance in physical and chemical properties between the eighth element and the first element [similar to the eighth and first notes on a musical scale]
For example:
The eighth element from Lithium is Sodium and from Fluorine is Chlorine which show similarity in properties.
In which way was Newland's Law of Octaves comparable to a musical note.
Elements when arranged in increasing order of their atomic weights show resemblance in physical and chemical properties between the eighth element and the first element similar to the eighth and first notes on a musical scale.
State how Mendeleeff arranged the elements in the periodic table. What was the basis of his classification.
Mendeleeff arranged elements in increasing order of their atomic weights in the form of a table called 'periodic table'.
This arrangement had elements with similar properties appearing at regular intervals.
This phenomenon is called 'periodicity of properties' and the properties which repeat themselves at regular intervals are called 'periodic properties'.
State Mendeleeff's Periodic Law.
How did Mendeleeff's arrangement of elements correlate with periodicity of properties of elements.
Mendeleeff's Periodic Law — The physical and chemical properties of elements are periodic functions of their atomic weights.
Mendeleeff's arrangement had elements with similar properties appearing at regular intervals. This phenomenon is called 'periodicity of properties' and the properties which repeat themselves at regular intervals are called 'periodic properties'. Some examples of periodic properties are atomic radius, ionisation potential, electron affinity, etc.
State the contributions made by Mendeleeff towards the periodic table.
The contributions of Mendeleeff towards the periodic table are:
State the defects and anomalies in Mendeleeff's Periodic Table and how were they resolved by Moseley?
Defects in Mendeleeff's Periodic Table :
Most of the defects in Mendeleeff's Periodic Table disappear if the basis of classification of elements is changed from atomic weights to atomic numbers.
Moseley arranged the elements in increasing order of atomic number in Seven horizontal rows called 'periods' and Eighteen vertical columns called 'groups'.
This forms the basis of the Modern Periodic Table.
How were elements arranged in the long form of the periodic table or the Modern Periodic Table. State the Modern Periodic Law and compare it with Mendeleeff's Periodic Law.
In the Modern Periodic Table elements are arranged in increasing order of atomic number.
Modern Periodic Law states that the physical and chemical properties of elements are periodic function of their 'atomic numbers'.
Mendeleeff's Periodic Law states that the physical and chemical properties of elements are periodic function of their 'atomic weights'.
The basis of classification in Mendeleeff's Periodic Law was atomic weight of the element whereas in the Modern Periodic Law it is the atomic number of elements. This change in the Modern Periodic Law solves most of the defects in Mendeleeff's Periodic table.
State what are periods in a periodic table. What is meant by 'period number'. What does it signify.
Periods in the periodic table are the seven horizontal rows of elements arranged in increasing order of their atomic numbers.
Period number is the number assigned to each period i.e., 1, 2, 3, 4, 5, 6 or 7. It signifies the number of shells present in the atom of the element belonging to that period.
Name the period which is the shortest period and state the number of elements present in it. State the number of elements in the second and the third periods of the periodic table.
Period 1 is the shortest period. It has 2 elements [H and He]
Second period has 8 elements.
Third period also has 8 elements.
Name the elements in the correct order of their increasing atomic numbers present in the first, second and third short periods of the periodic table.
State which of the elements are – (a) metallic (b) non-metallic (c) noble gases in each of the periods 2 and 3.
Period 1 — 1H, 2He
Period 2 — 3Li, 4Be, 5B, 6C, 7N, 8O, 9F, 10Ne
Period 3 — 11Na, 12Mg, 13Al, 14Si, 15P, 16S, 17Cl, 18Ar
The metallic, non-metallic and noble gas elements of periods 2 and 3 are listed below:
Period 2: Metallic — Li, Be; Metalloid — B; Non-metallic — C, N, O, F; Noble gas — Ne
Period 3: Metallic — Na, Mg, Al; Metalloid — Si; Non-metallic — P, S, Cl; Noble gas — Ar
State the property trends in general of elements on moving from left to right in a period of the periodic table.
Property trends of elements from left to right in a period
(a) Number of electron shells — remain the same.
(b) Valence electrons — increases by one.
(c) Transition from metallic to non-metallic character.
(d) Electronegativity increases.
State what are -
(i) groups in a periodic table.
(ii) property trends in general of elements on moving down in a group of the periodic table.
(iii) the characteristics which remain similar on moving down in a group of the periodic table.
Eighteen vertical columns in the periodic table are called groups.
Trends on moving down in a group of the periodic table :
Write short notes on the following types of elements –
(a) alkali metals
(b) alkaline earth metals
(c) halogens
(d) noble gases
(e) transition and inner transition elements
(f) normal elements
(a) Alkali metals —
(b) Alkaline earth metals —
(c) Halogens —
(d) Noble gases —
(e) Transition and inner transition elements —
Transition elements —
Inner transition elements —
(f) Normal elements —
The element which is univalent & a strong reducing agent, present in the same period as the element having two electron shells with eight electrons in valence shell.
Li
Reason — The element having two electron shells with eight electrons in the outer valence shell is Neon and Neon is in Period 2. We need an element in the same period that is univalent & a strong reducing agent.
In Period 2, the elements are:
Li, Be, B, C, N, O, F, Ne
Among these, Lithium is univalent as it has valency 1 and a strong reducing agent because it is an electron donor.
Fluorine and Chlorine are strong oxidising agents as they are electron acceptors. Sodium, though a reducing agent and univalent but it is in Period 3.
A solid univalent element which is a strong oxidising agent & present in the group 'X' which means salt producer.
I
Reason — Iodine is a solid halogen, univalent as it has one valency and acts as an oxidising agent as it is an electron acceptor.
Fluorine is not solid at room temperature; it is a gas. Silicon is not a halogen; it belongs to Group 14. Boron belongs to Group 13, not the halogens.
Assertion: Valency or combining capacity of noble gas is zero.
Reason: Noble gases are monoatomic gases.
Both A and R are true but R is not the correct explanation of A.
Reason — A is true as noble gases already have a completely filled outermost shell (stable electronic configuration), so they neither gain, lose, nor share electrons easily.
R is true as noble gases exist as single atoms because they are chemically inert.
However, being monoatomic is a result of their stable electronic configuration, not the reason for their zero valency. The correct explanation for zero valency is their complete outermost shell, not their monoatomic nature.
Therefore, Both A and R are true and R is not the correct explanation of A is the correct option.
Select the incorrect statement.
Chlorine is more electronegative than fluorine, but less electronegative than bromine.
Reason — Electronegativity order among halogens is:
F > Cl > Br
So chlorine is less electronegative than fluorine and more electronegative than bromine.
Fluorine is the most electronegative element.
| Period | 1 (1A) | 2 | Group 13 | Group 14 | Group 15 | Group 16 | Group 17 (VIIA) | Group 18 (0) |
|---|---|---|---|---|---|---|---|---|
| 1 | 1H | 2He | ||||||
| 2 | 3Li | C | O | F | 10Ne | |||
| 3 | 11Na | 12Mg | P | R | 18Ar | |||
| 4 | A | B | X | Y |
(i) From 'A', 'B', 'X', 'Y', state which is (a) divalent (b) a strong reducing agent (c) unreactive.
(ii) From 'R' & 'X', state which (a) is a liquid (b) more electronegative (c) less non-metallic.
(iii) The number of electron shells in (a) 3Li (b) 12Mg (c) B (d) 18Ar (e) X
(iv) The number of valence electrons in (a) 11Na (b) B (c) R (d) Ar
(v) The strong reducing agent from A & B
(vi) From Li, Na & Mg which are the (a) Normal elements (b) Bridge elements (c) Alkali metals
(vii) State the valency of (a) R (b) Y
(viii) From R, A & Y, state which are the (a) metals (b) Non-metal/s
(ix) From elements in period 2 — Li, C & F — state which element/s shows allotropy.
(x) Give a reason why elements — F, R & X show similar chemical properties.
(i)
(a) B is divalent.
(b) A is strong reducing agent.
(c) Y is unreactive.
(ii)
(a) X is a liquid.
(b) R is more electronegative.
(c) X is less non-metallic.
(iii) The numbers of electron shells are:
(a) Li — 2 (b) Mg — 3 (c) B — 4 (d) Ar — 3 (e) X — 4
(iv) The numbers of valence electrons are:
(a) Na — 1 (b) B — 2 (c) R — 7 (d) Ar — 8
(v) A is the stronger reducing agent.
(vi)
(a) Li, Na and Mg are normal elements.
(b) Li and Mg are bridge elements because they show diagonal relationship.
(c) Li and Na are alkali metals.
(vii)
(a) Valency of R = 1
(b) Valency of Y = 0
(viii)
(a) A is a metal.
(b) R and Y are non-metals.
(ix) C shows allotropy.
(x) F, R and X show similar chemical properties because they belong to the same group, Group 17, and have the same number of valence electrons, i.e. 7.
State the non-metallic element in the period having the metalloid with three valence electrons which is diatomic & unreactive at ordinary temperatures.
The metalloid with three valence electrons is boron, which belongs to Period 2. The non-metallic element in the same period which is diatomic and unreactive at ordinary temperatures is nitrogen, which exists as N2.
State the most electronegative element from the elements chlorine, bromine & iodine in group 17 (VIIA) and the least non-metallic element from carbon, oxygen & fluorine in period 2.
Most electronegative element in group 17 is chlorine as electronegativity decreases down Group 17. Least non-metallic element is carbon as non-metallic character increases across a period from left to right.
C < O < F
Select the correct answer from the words in bracket.
Fill in the blanks from the words A to F given below.
A: Decreases B: Increases C: Remains same D: Increases by one E: Electropositive F: Electronegative
Give reasons for the following.
Mendeleeff's contributions to the periodic table, laid the foundation for the Modern Periodic Table.
Mendeleeff's contributions to the periodic table laid the foundation for the Modern Periodic Table because he arranged elements in increasing order of their atomic weights in horizontal rows called 'periods' and vertical columns called 'groups'. His arrangement showed that:
Give reasons for the following.
Properties of elements are periodic functions of their atomic numbers and not atomic weights.
The properties of elements are dependent on the electronic configuration of their atoms. As similar electronic configurations repeat after regular intervals of atomic numbers hence properties of elements are periodic functions of their atomic numbers and not atomic weights.
This was seen when Mendeleeff arranged the elements on the basis of their atomic weights. Certain defects were present in Mendeleeff's periodic table which got removed when elements were arranged as per their atomic numbers.
Give reasons for the following.
A transition from metallic to non-metallic elements is seen on moving from left to right in a period of the periodic table.
On moving across a period, the tendency to gain electron(s) increases due to an increase in nuclear pull and a decrease in the atomic size. Therefore, non-metallic character increases across a period and there is a transition from metallic to non-metallic elements.
Give reasons for the following.
Noble gases do not form compounds readily.
Noble gases have their outermost or valence shell complete i.e., they have 2 electrons in outermost shell e.g., helium [electronic configuration 2] or they have 8 electrons in outermost shell e.g., neon [electronic configuration 2,8] or argon [electronic configuration 2,8,8 ]. So, they have stable electronic configuration. They do not gain, lose or share electrons and are unreactive or inert. Hence, they do not form compounds readily.
Give reasons for the following.
Group 1 [IA] elements are called alkali metals.
Elements of Group 1 [IA] are metals and react with water to form alkalis, hence are called alkali metals.
State the following.
Match the elements of List-I with their type from List-II.
| List I | List II |
|---|---|
| 1. Highly reactive, univalent metals | A: Halogens |
| 2. Highly reactive, univalent non-metals | B: Transition elements |
| 3. Unreactive, inert elements | C: Alkali metals |
| 4. Elements of group 3 to 12 [IB to VIIB and VIII] | D: Lanthanide series |
| 5. Radioactive elements | E: Noble gases |
| F: Actinide series |
| List I | List II |
|---|---|
| 1. Highly reactive, univalent metals | C: Alkali metals |
| 2. Highly reactive, univalent non-metals | A: Halogens |
| 3. Unreactive, inert elements | E: Noble gases |
| 4. Elements of group 3 to 12 [IB to VIIB and VIII] | B: Transition elements |
| 5. Radioactive elements | F: Actinide series |
Complete the table pertaining to the following elements given in Column 1.
| Column 1 Elements | Atomic number | Electronic configuration | Underline the element present in that group |
|---|---|---|---|
| 1. Hydrogen | 1 | ..... | Be/Na/Ca/ |
| 2. Carbon | 6 | ....., ..... | N/P/Si |
| 3. Nitrogen | 7 | ....., ..... | C/P/S |
| 4. Oxygen | 8 | ....., ..... | N/S/Cl |
| 5. Sulphur | 16 | ....., ....., ..... | O/N/F |
| 6. Chlorine | 17 | ....., ....., ..... | I/O/S |
| Column 1 Elements | Atomic number | Electronic configuration | Underline the element present in that group |
|---|---|---|---|
| 1. Hydrogen | 1 | 1 | Na |
| 2. Carbon | 6 | 2, 4 | Si |
| 3. Nitrogen | 7 | 2, 5 | P |
| 4. Oxygen | 8 | 2, 6 | S |
| 5. Sulphur | 16 | 2, 8, 6 | O |
| 6. Chlorine | 17 | 2, 8, 7 | I |
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