Given elements are:
$^{35}_{17}\text X \quad \text{and} \quad ^{40}_{20}\text Y$
So, atomic number of X = 17 and atomic number of Y = 20.
(a) Group and period of X and Y
For X:
Atomic number = 17
Electronic configuration = 2, 8, 7
Since X has 3 shells, it belongs to Period 3. Since X has 7 valence electrons, it belongs to Group 17.
For Y:
Atomic number = 20
Electronic configuration = 2, 8, 8, 2
Since Y has 4 shells, it belongs to Period 4. Since Y has 2 valence electrons, it belongs to Group 2.
(b) Nature of X and Y
- X is a non-metal, while Y is a metal.
- X is an oxidising agent, as it tends to gain electrons.
Y is a reducing agent, as it tends to lose electrons.
(c) Formation and properties of compound:
Yes, X and Y can combine to form a compound.
Y loses two electrons to form a Y2+ ion. Each X atom gains one electron to form an X- ion.
Hence, X and Y can combine and form an ionic compound.
Three properties of this compound are:
- The compound has high melting and boiling point.
- It conducts electricity in molten or aqueous state.
- It is soluble in water.
(d) Formula of their oxides:
- Oxide of X ⇒ X2O7
(As X is Chlorine [Cl], hence formula of its oxide will be Cl2O7) - Oxide of Y ⇒ YO
(As Y is Calcium [Ca], hence formula of its oxide will be CaO)
Explanation:
For X:
X has atomic number 17 and electronic configuration 2, 8, 7. It belongs to Group 17. Its valency with respect to oxygen is 7.
Oxygen has valency 2.
$\text{X}^{7} \quad \text{O}^{2}$
By criss-crossing the valencies, the formula of the oxide of X is:
$\text{X}_2\text{O}_7$
For Y:
Y has atomic number 20 and electronic configuration 2, 8, 8, 2. It belongs to Group 2. Hence, its valency is 2.
Oxygen also has valency 2.
$\text{Y}^{2} \quad \text{O}^{2}$
By criss-crossing and simplifying, the formula of the oxide of Y is:
$\text{YO}$
Hence, the formulae of their oxides are:
X2O7 and YO