Algebraic Expressions

ICSE Class 7 Mathematics · Solutions for Class 7 RS Aggarwal ICSE Foundation Mathematics · 43 solved questions

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1Exercise 13(A)

Identify monomials, binomials and trinomials from the following algebraic expressions.

(i) 7p2 × a3b

(ii) 5 + 3x3y3z2

(iii) 3x2 ÷ p

(iv) $\frac{3a + 2b - 5c}{7}$

(v) xy + yz - zx

(vi) ax2 + bx × y2

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(i) 7p2 × a3b

Multiplication combines these into a single unit. There are no + or - signs separating them.

Number of terms: 1

Hence, it is a monomial.

(ii) 5 + 3x3y3z2

The + sign separates the constant '5' from the variable term.

Number of terms: 2

Hence, it is a binomial.

(iii) 3x2 ÷ p

Division results in a single algebraic term : $\frac{3\text x^2}{\text p}$

So,

Number of terms: 1

Hence, it is a monomial.

(iv) $\frac{3a + 2b - 5c}{7}$

While the entire expression is over a single denominator, the numerator contains three distinct terms (3a, 2b, and -5c) separated by + and -.

⟹ Number of terms: 3

Hence, it is a trinomial.

(v) xy + yz - zx

There are three distinct products separated by + and -.

So,

Number of terms: 3

Hence, it is a trinomial.

(vi) ax2 + bx × y2

The multiplication combines bx and y2 into one term (bxy2). The only separator is the + sign.

Term 1: ax2

Term 2: bxy2

Number of terms: 2

Hence, it is a binomial.

2Exercise 13(A)

Write down the numerical as well as literal coefficient of each of the following monomials:

(i) -2p3q2

(ii) $\frac{5}{9}xyz^2$

(iii) $-\frac{3ab^2}{2}$

(iv) $\frac{3}{a^2}$

(v) $\frac{2ab}{c}$

(vi) $-\frac{2x^2}{yz}$

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(i) -2p3q2

Numerical coefficient = −2, Literal coefficient = p3q2

(ii) $\frac{5}{9}xyz^2$

Numerical coefficient = $\frac{5}{9}$, Literal coefficient = xyz2

(iii) $-\frac{3ab^2}{2}$

Numerical coefficient = $-\frac{3}{2}$, Literal coefficient = ab2

(iv) $\frac{3}{a^2}$

Numerical coefficient = 3, Literal coefficient = $\frac{1}{a^2}$

(v) $\frac{2ab}{c}$

Numerical coefficient = 2, Literal coefficient = $\frac{ab}{c}$

(vi) $-\frac{2x^2}{yz}$

Numerical coefficient = -2, Literal coefficient = $\frac{x^2}{yz}$

3Exercise 13(A)

In -5p2q3r4, write down the coefficient of:

(i) p2

(ii) 5pq2

(iii) p2q2

(iv) pqr

(v) -pq2r3

(vi) 5q3r

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(i) p2

Coefficient of p2:

Divide the original expression by p2 then

-5p2q3r4 ÷ p2

= -5q3r4

∴ Coefficient of p2 is -5q3r4

(ii) 5pq2

Coefficient of 5pq2:

Divide the original expression by 5pq2 then

-5p2q3r4 ÷ 5pq2

= -pqr4

∴ Coefficient of 5pq2 is -pqr4

(iii) p2q2

Coefficient of p2q2:

Divide the original expression by p2q2 then

-5p2q3r4 ÷ p2q2

= -5qr4

∴ Coefficient of p2q2 is -5qr4

(iv) pqr

Coefficient of pqr:

Divide the original expression by pqr then

-5p2q3r4 ÷ pqr

= -5pq2r3

∴ Coefficient of pqr is -5pq2r3

(v) -pq2r3

Coefficient of -pq2r3:

Divide the original expression by -pq2r3 then

-5p2q3r4 ÷ -pq2r3

= 5pqr

∴ Coefficient of -pq2r3 is 5pqr

(vi) 5q3r

Coefficient of 5q3r:

Divide the original expression by 5q3r then

-5p2q3r4 ÷ 5q3r

= -p2r3

∴ Coefficient of 5q3r is -p2r3

4Exercise 13(A)

Identify like terms in the following:

(i) a2, b2, -2a2, c2, 4a

(ii) 3x, 4xy, -yz, $\frac{1}{2}$zy

(iii) -2xy2, x2y, 5y2x, x2z

(iv) abc, ab2c, acb2, c2ab, b2ac, a2bc, cab2

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(i) a2, b2, -2a2, c2, 4a

Since a2 and -2a2 have the same literal part

∴ Like terms are a2 and -2a2.

(ii) 3x, 4xy, -yz, $\frac{1}{2}$zy

Since -yz and $\frac{1}{2}$zy have the same literal part

∴ Like terms are -yz and $\frac{1}{2}$zy.

(iii) -2xy2, x2y, 5y2x, x2z

Since -2xy2 and 5y2x have the same literal part

∴ Like terms are -2xy2 and 5y2x.

(iv) abc, ab2c, acb2, c2ab, b2ac, a2bc, cab2

Since ab2c, acb2, b2ac and cab2 have the same literal part

∴ Like terms are ab2c, acb2, b2ac and cab2.

5Exercise 13(A)

Generate algebraic expressions for the following:

(i) The product of a and b added to their sum.

(ii) The quotient of x by 8 is multiplied by y.

(iii) Thrice x added to y squared.

(iv) One-third of x multiplied by the sum of p and q.

(v) The number to be added to x + y to make it equal to p.

(vi) From a rod (p + q) units in length, n equal pieces are cut. Find the length of each piece.

(vii) Five times m subtracted from the sum of p and thrice x.

(viii) The number obtained when m times the difference of x and y is subtracted from n times the sum of x and y.

(ix) The sum of 7 numbers each equal to p.

(x) The product of three numbers a, b and c subtracted from the sum of x and y.

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(i) The product of a and b added to their sum.

Product of a and b = ab

Sum of a and b = (a + b)

∴ The expression is (a + b) + ab

(ii) The quotient of x by 8 is multiplied by y.

Quotient of x by 8 = $\frac{x}{8}$

Multiplied by y = $\frac{x}{8} \times y$

∴ The expression is $\frac{x}{8} \times y$

(iii) Thrice x added to y squared.

Thrice x = 3x

y squared = y2

∴ The expression is y2 + 3x

(iv) One-third of x multiplied by the sum of p and q.

One-third of x = $\frac{1}{3}x$

Sum of p and q = (p + q)

∴ The expression is $\frac{1}{3}x(p + q)$

(v) The number to be added to x + y to make it equal to p.

Let number = ?

x + y + ? = p

⇒ ? = p − (x + y)

∴ The expression is p - (x + y)

(vi) From a rod (p + q) units in length, n equal pieces are cut. Find the length of each piece.

Total length = p + q

Number of pieces = n

Length of each piece = $\frac{\text{Total length}}{\text{Number of pieces}}$

Length of each piece = $\frac{p + q}{n}$

∴ The expression is $\frac{p + q}{n}$

(vii) Five times m subtracted from the sum of p and thrice x.

Five times m = 5m

Sum of p and thrice x = (p + 3x)

∴ The expression is (p + 3x) - 5m

(viii) The number obtained when m times the difference of x and y is subtracted from n times the sum of x and y.

Difference of x and y = (x − y)

m times difference = m(x - y)

Sum of x and y = x + y

n times sum = n(x + y)

∴ The expression is n(x + y) - m(x - y)

(ix) The sum of 7 numbers each equal to p.

Adding p seven times is the same as 7 multiplied by p.

∴ The expression is 7p

(x) The product of three numbers a, b and c subtracted from the sum of x and y.

Product of a, b, c = abc

Sum of x and y = x + y

∴ The expression is (x + y) - abc

6Exercise 13(A)

Identify which of the following expressions are polynomials. If so, write their degrees.

(i) $\frac{2}{3}x^4 - 7x + 15$

(ii) 8x2 - 3x + 6√x + 1

(iii) 5x2 - $\frac{2}{x}$ + 7

(iv) 9x2y2 - 3xy2 + 5x2y - 6x

(v) 6p4 - p3q2 + pq3 + q4

(vi) 4x5 - 7x5y + 3xy4 + 8y5

(vii) ab2 - $\frac{7}{a^2}$ + 5b2 + 6

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(i) $\frac{2}{3}x^4 - 7x + 15$

All powers of x are whole numbers.

The highest power of x is 4.

Yes, it is a polynomial. Degree = 4

(ii) 8x2 - 3x + 6√x + 1

The term 6√x can be written as 6x1/2, 1/2 is not a whole number.

∴ It is not a polynomial.

(iii) 5x2 - $\frac{2}{x}$ + 7

The term $\frac{2}{x}$ can be written as 2x-1, power of x is a negative integer.

∴ It is not a polynomial.

(iv) 9x2y2 - 3xy2 + 5x2y - 6x

All powers of x and y are whole numbers.

Degrees of terms:

9x2y2 → 2 + 2 = 4

3xy2 → 1 + 2 = 3

5x2y → 2 + 1 = 3

6x → 1

The highest degree is 4.

Yes, it is a polynomial. Degree = 4

(v) 6p4 - p3q2 + pq3 + q4

All powers of p and q are whole numbers.

Degrees of terms:

6p4 → 4

p3q2 → 3 + 2 = 5

pq3 → 1 + 3 = 4

q4 → 4

The highest degree is 5.

Yes, it is a polynomial. Degree = 5

(vi) 4x5 - 7x5y + 3xy4 + 8y5

All powers of x and y are whole numbers.

Degrees of terms:

4x5 → 5

7x5y → 5 + 1 = 6

3xy4 → 1 + 4 = 5

8y5 → 5

The highest degree is 6.

Yes, it is a polynomial. Degree = 6

(vii) ab2 - $\frac{7}{a^2}$ + 5b2 + 6

The term $\frac{7}{a^2}$ means 7a-2, power of a is a negative integer.

∴ It is not a polynomial.

1Exercise 13(B)

Add the following expressions:

(i) 2x2, -5x2, -x2, 6x2

(ii) x2 - 2xy + 3y2, 5y2 + 3xy - 6x2

(iii) 2x + 9y - 7z, 3y + z - 3x, 2z - 4y - x

(iv) 2ab + 3bc - 5ca, 4bc - 3ab + 7ca, 2ca - ab - 5bc

(v) 3x3 + 2x2 - 6x + 3, 2x3 - 3x2 - x - 4, 1 + 2x - 3x2 - 4x3

(vi) 3n2 + 5mn - 6m2, 2m2 - 3mn - 4n2, 2mn - 3m2 - 7n2

(vii) 3z3 - z2 + 5, 1 - 2z + z2, 3 + 2z - z3

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(i) 2x2, -5x2, -x2, 6x2

Since these are all like terms, we can stack them in a single column:

$$\begin{array}{r} 2x^2 \\ -5x^2 \\ -\phantom{5} x^2 \\ +6x^2 \\ \hline 2x^2 \\ \hline \end{array}$$

Hence, the answer is 2x2

(ii) x2 - 2xy + 3y2, 5y2 + 3xy - 6x2

Arranging the expressions so that x2 is under x2, xy is under xy, and y2 is under y2:

$$\begin{array}{rcccc} x^2 & - & 2xy & + & 3y^2 \\ -6x^2 & + & 3xy & + & 5y^2 \\ \hline -5x^2 & + & xy & + & 8y^2 \\ \hline \end{array}$$

Hence, the answer is -5x2 + xy + 8y2

(iii) 2x + 9y - 7z, 3y + z - 3x, 2z - 4y - x

Arranging the expressions so that x is under x, y is under y, and z is under z:

$$\begin{array}{rcccc} 2x & + & 9y & - & 7z \\ -3x & + & 3y & + & z \\ -\phantom{3} x & - & 4y & + & 2z \\ \hline -2x & + & 8y & - & 4z \\ \hline \end{array}$$

Hence, the answer is -2x + 8y - 4z

(iv) 2ab + 3bc - 5ca, 4bc - 3ab + 7ca, 2ca - ab - 5bc

Arranging the expressions so that ab is under ab, bc is under bc, and ca is under ca:

$$\begin{array}{rcccc} 2ab & + & 3bc & - & 5ca \\ -3ab & + & 4bc & + & 7ca \\ -\phantom{3} ab & - & 5bc & + & 2ca \\ \hline -2ab & + & 2bc & + & 4ca \\ \hline \end{array}$$

Hence, the answer is -2ab + 2bc + 4ca

(v) 3x3 + 2x2 - 6x + 3, 2x3 - 3x2 - x - 4, 1 + 2x - 3x2 - 4x3

Arranging the expressions into descending powers of x (x3, x2, x, constant):

$$\begin{array}{rcccccc} 3x^3 & + & 2x^2 & - & 6x & + & 3 \\ +2x^3 & - & 3x^2 & - & x & - & 4 \\ -4x^3 & - & 3x^2 & + & 2x & + & 1 \\ \hline x^3 & - & 4x^2 & - & 5x & + & 0 \\ \hline \end{array}$$

Hence, the answer is x3 - 4x2 - 5x

(vi) 3n2 + 5mn - 6m2, 2m2 - 3mn - 4n2, 2mn - 3m2 - 7n2

Arranging the expressions so that m2 is under m2, mn is under mn, and n2 is under n2:

$$\begin{array}{rcccc} -6m^2 & + & 5mn & + & 3n^2 \\ +2m^2 & - & 3mn & - & 4n^2 \\ -3m^2 & + & 2mn & - & 7n^2 \\ \hline -7m^2 & + & 4mn & - & 8n^2 \\ \hline \end{array}$$

Hence, the answer is -7m2 + 4mn - 8n2

(vii) 3z3 - z2 + 5, 1 - 2z + z2, 3 + 2z - z3

Arranging the expressions in descending powers of z and use 0 as a placeholder for any missing terms:

$$\begin{array}{rcccccc} 3z^3 & - & z^2 & + & 0 & + & 5 \\ +\phantom{3} 0 & + & z^2 & - & 2z & + & 1 \\ -z^3 & + & 0 & + & 2z & + & 3 \\ \hline 2z^3 & + & 0 & + & 0 & + & 9 \\ \hline \end{array}$$

Hence, the answer is 2z3 + 9

2Exercise 13(B)

Simplify:

(i) 5x + 3y - 8z + 2y - 3x + 5z + z - 7y - 2x

(ii) 4x3 - 2x2 + 5x - 1 + 8x + x2 - 6x3 + 7 - 6x + 3 - 3x2 - x3

(iii) 2x2 + 3xy - 3y2 + x2 - xy + y2

(iv) 2 - 3z2 + 5yz + 7y2 - 8 + z2 - 6yz - 9y2 + 1 - 2z2 - 2yz - y2

(v) 2m - 3n + 5p + 2m + n - 2p - 3m - 4n + p

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(i) 5x + 3y - 8z + 2y - 3x + 5z + z - 7y - 2x

Arranging the like terms together, we have:

5x + 3y - 8z + 2y - 3x + 5z + z - 7y - 2x

= (5x - 3x - 2x) + (3y + 2y - 7y) + (-8z + 5z + z)

Combining coefficients:

= (5 - 3 - 2)x + (3 + 2 - 7)y + (-8 + 5 + 1)z

= (0)x + (-2)y + (-2)z

= -2y - 2z

Hence, the answer is -2y - 2z

(ii) 4x3 - 2x2 + 5x - 1 + 8x + x2 - 6x3 + 7 - 6x + 3 - 3x2 - x3

Arranging the like terms together, we have:

4x3 - 2x2 + 5x - 1 + 8x + x2 - 6x3 + 7 - 6x + 3 - 3x2 - x3

= (4x3 - 6x3 - x3) + (-2x2 + x2 - 3x2) + (5x + 8x - 6x) + (-1 + 7 + 3)

Combining coefficients:

= (4 - 6 - 1)x3 + (-2 + 1 - 3)x2 + (5 + 8 - 6)x + (9)

= (-3)x3 + (-4)x2 + (7)x + 9

= -3x3 - 4x2 + 7x + 9

Hence, the answer is -3x3 - 4x2 + 7x + 9

(iii) 2x2 + 3xy - 3y2 + x2 - xy + y2

Arranging the like terms together, we have:

2x2 + 3xy - 3y2 + x2 - xy + y2

= (2x2 + x2) + (3xy - xy) + (-3y2 + y2)

Combining coefficients:

= (2 + 1)x2 + (3 - 1)xy + (-3 + 1)y2

= 3x2 + 2xy - 2y2

Hence, the answer is 3x2 + 2xy - 2y2

(iv) 2 - 3z2 + 5yz + 7y2 - 8 + z2 - 6yz - 9y2 + 1 - 2z2 - 2yz - y2

Arranging the like terms together, we have:

2 - 3z2 + 5yz + 7y2 - 8 + z2 - 6yz - 9y2 + 1 - 2z2 - 2yz - y2

= (2 - 8 + 1) + (-3z2 + z2 - 2z2) + (5yz - 6yz - 2yz) + (7y2 - 9y2 - y2)

Combining coefficients:

= (-5) + (-3 + 1 - 2)z2 + (5 - 6 - 2)yz + (7 - 9 - 1)y2

= -5 + (-4)z2 + (-3)yz + (-3)y2

= -5 - 4z2 - 3yz - 3y2

Hence, the answer is -5 - 4z2 - 3yz - 3y2

(v) 2m - 3n + 5p + 2m + n - 2p - 3m - 4n + p

Arranging the like terms together, we have:

2m - 3n + 5p + 2m + n - 2p - 3m - 4n + p

= (2m + 2m - 3m) + (-3n + n - 4n) + (5p - 2p + p)

Combining coefficients:

= (2 + 2 - 3)m + (-3 + 1 - 4)n + (5 - 2 + 1)p

= (1)m + (-6)n + (4)p

= m - 6n + 4p

Hence, the answer is m - 6n + 4p

3Exercise 13(B)

The two adjacent sides of a rectangle are 3a - b and 6b - a. Find its perimeter.

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Given:

Length = (3a - b)

Breadth = (6b - a)

Perimeter of a rectangle = 2 x (Length + Breadth)

Substituting the values above, we get:

Perimeter of a rectangle = 2 x (3a - b + 6b - a)

= 2 x [(3a - a) + (-b + 6b)] $\quad$[Grouping like terms]

= 2 x (2a + 5b) $\quad$[Distributive property of multiplication]

= 4a + 10b

The perimeter of the rectangle is 4a + 10b.

4Exercise 13(B)

Find the perimeter of a triangle whose sides are 2y + 3z, z - y, 4y - 2z.

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Given:

Side 1 = 2y + 3z

Side 2 = z - y

Side 3 = 4y - 2z

Perimeter of a triangle = Side 1 + Side 2 + Side 3

Substituting the values above, we get:

Perimeter of a triangle = (2y + 3z + z - y + 4y - 2z)

= (2y - y + 4y) + (3z + z - 2z) $\quad$[Grouping like terms]

= (2 - 1 + 4)y + (3 + 1 - 2)z $\quad$[Combining coefficients]

= 5y + 2z

The perimeter of the triangle is 5y + 2z.

5Exercise 13(B)

Subtract:

(i) 3a - 2b + 4c from 5a - 3b - 5c

(ii) 5x2 - 3xy - 7y2 from 3x2 - xy - 2y2

(iii) 3p3 - 5p2q + 2q2 from q2 + p2q - 4p3

(iv) ab - bc - ca from 3ab + 2bc - 4ca

(v) 3z3 - 2z2 + 7z - 8 from 8 - z - z2

(vi) 2abc - a2 - b2 from b2 + a2 - 2abc

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(i) 3a - 2b + 4c from 5a - 3b - 5c

We have:

$$\begin{array}{rcccc} 5a & - & 3b & - & 5c \\ +3a & - & 2b & + & 4c \\ -\phantom{3a} & + & & - \\ \hline 2a & - & b & - & 9c \\ \hline \end{array}$$

Hence, the answer is 2a - b - 9c

(ii) 5x2 - 3xy - 7y2 from 3x2 - xy - 2y2

We have:

$$\begin{array}{rcccc} 3x^2 & - & xy & - & 2y^2 \\ +5x^2 & - & 3xy & - & 7y^2 \\ -\phantom{5x^2} & + & & + \\ \hline -2x^2 & + & 2xy & + & 5y^2 \\ \hline \end{array}$$

Hence, the answer is -2x2 + 2xy + 5y2

(iii) 3p3 - 5p2q + 2q2 from q2 + p2q - 4p3

Arranging the terms to match (p3, p2q, q2):

$$\begin{array}{rcc} -4p^3 & + & p^2q & + & q^2 \\ +3p^3 & - & 5p^2q & + & 2q^2 \\ -\phantom{3p^3} & + & & - \\ \hline -7p^3 & + & 6p^2q & - & q^2 \\ \hline \end{array}$$

Hence, the answer is -7p3 + 6p2q - q2

(iv) ab - bc - ca from 3ab + 2bc - 4ca

Arranging the terms to match(ab, bc, ca):

$$\begin{array}{rcccc} 3ab & + & 2bc & - & 4ca \\ +ab & - & bc & - & ca \\ -\phantom{ab} & + & & + \\ \hline 2ab & + & 3bc & - & 3ca \\ \hline \end{array}$$

Hence, the answer is 2ab + 3bc - 3ca

(v) 3z3 - 2z2 + 7z - 8 from 8 - z - z2

Arranging the expressions in ascending powers of z and use 0 as a placeholder for any missing terms:

$$\begin{array}{rcccccc} 8 & - & z & - & z^2 & + & 0 \\ -8 & + & 7z & - & 2z^2 & + & 3z^3 \\ +\phantom{8} & - & & + & & - \\ \hline 16 & - & 8z & + & z^2 & - & 3z^3 \\ \hline \end{array}$$

Hence, the answer is 16 - 8z + z2 - 3z3

(vi) 2abc - a2 - b2 from b2 + a2 - 2abc

Arranging the terms to match (a2, b2, abc):

$$\begin{array}{rcc} a^2 & + & b^2 & - & 2abc \\ -a^2 & - & b^2 & + & 2abc \\ +\phantom{a^2} & + & & - \\ \hline 2a^2 & + & 2b^2 & - & 4abc \\ \hline \end{array}$$

Hence, the answer is 2a2 + 2b2 - 4abc

6Exercise 13(B)

(i) Subtract 6x3 - 5x2 + 4x - 3 from the sum of x + 2x2 - 3x3 and 2 - x2 + 6x - x3.

(ii) Subtract the sum of a + 2b - 3c and 2c - 3b - 4a from the sum of 5b - 4c + a and 2c - 3b - 4a.

(iii) Subtract the sum of x2 - 5xy + 2y2 and y2 - 2xy - 3x2 from the sum of 6x2 - 8xy - y2 and 2xy - 2y2 - x2.

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(i) Subtract 6x3 - 5x2 + 4x - 3 from the sum of x + 2x2 - 3x3 and 2 - x2 + 6x - x3.

Let's find the sum of the last two expressions:

We have:

x + 2x2 - 3x3 and 2 - x2 + 6x - x3

Arranging the terms in descending powers of x and use 0 as a placeholder for any missing term:

$$\begin{array}{rcccccc} -3x^3 & + & 2x^2 & + & x & + & 0 \\ -\phantom{3} x^3 & - & x^2 & + & 6x & + & 2 \\ \hline -4x^3 & + & x^2 & + & 7x & + & 2 \\ \hline \end{array}$$

The sum is -4x3 + x2 + 7x + 2

Now, subtract 6x3 - 5x2 + 4x - 3 from the above sum:

$$\begin{array}{rcccccc} -4x^3 & + & x^2 & + & 7x & + & 2 \\ +6x^3 & - & 5x^2 & + & 4x & - & 3 \\ -\phantom{6x^3} & + & & - & & + \\ \hline -10x^3 & + & 6x^2 & + & 3x & + & 5 \\ \hline \end{array}$$

Hence, the answer is -10x3 + 6x2 + 3x + 5

(ii) Subtract the sum of a + 2b - 3c and 2c - 3b - 4a from the sum of 5b - 4c + a and 2c - 3b - 4a.

Let's find the sum of first pair:

We have:

a + 2b - 3c and 2c - 3b - 4a

Arranging the terms to match (a, b, c):

$$\begin{array}{rcccc} a & + & 2b & - & 3c \\ -4a & - & 3b & + & 2c \\ \hline -3a & - & b & - & c \\ \hline \end{array}$$

Sum 1 = -3a - b - c

Now, let's find the sum of second pair:

We have:

5b - 4c + a and 2c - 3b - 4a

Arranging the terms to match (a, b, c):

$$\begin{array}{rcccc} a & + & 5b & - & 4c \\ -4a & - & 3b & + & 2c \\ \hline -3a & + & 2b & - & 2c \\ \hline \end{array}$$

Sum 2 = -3a + 2b - 2c

Let's subtract sum 1 from sum 2:

$$\begin{array}{rcccc} -3a & + & 2b & - & 2c \\ -3a & - & b & - & c \\ +\phantom{3a} & + & & + \\ \hline 0 & + & 3b & - & c \\ \hline \end{array}$$

Hence, the answer is 3b - c

(iii) Subtract the sum of x2 - 5xy + 2y2 and y2 - 2xy - 3x2 from the sum of 6x2 - 8xy - y2 and 2xy - 2y2 - x2.

Let's find the sum of first pair:

We have:

x2 - 5xy + 2y2 and y2 - 2xy - 3x2

Arranging the terms to match (x2, xy, y2):

$$\begin{array}{rcccc} x^2 & - & 5xy & + & 2y^2 \\ -3x^2 & - & 2xy & + & y^2 \\ \hline -2x^2 & - & 7xy & + & 3y^2 \\ \hline \end{array}$$

Sum 1 = -2x2 - 7xy + 3y2

Now, let's find the sum of second pair:

We have:

6x2 - 8xy - y2 and 2xy - 2y2 - x2

Arranging the terms to match (x2, xy, y2):

$$\begin{array}{rcccc} 6x^2 & - & 8xy & - & y^2 \\ -x^2 & + & 2xy & - & 2y^2 \\ \hline 5x^2 & - & 6xy & - & 3y^2 \\ \hline \end{array}$$

Sum 2 = 5x2 - 6xy - 3y2

Let's subtract sum 1 from sum 2:

$$\begin{array}{rcccc} 5x^2 & - & 6xy & - & 3y^2 \\ -2x^2 & - & 7xy & + & 3y^2 \\ +\phantom{2x^2} & + & & - \\ \hline 7x^2 & + & xy & - & 6y^2 \\ \hline \end{array}$$

Hence, the answer is 7x2 + xy - 6y2

7Exercise 13(B)

(i) What should be subtracted from x + 2y - 3z to get 3x - 2y + z?

(ii) What should be subtracted from 2x2 - y2 + 4z2 to get x2 + y2 - z2?

(iii) What should be subtracted from 1 + x - x2 to get 2x + x2?

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(i) What should be subtracted from x + 2y - 3z to get 3x - 2y + z?

To find what must be subtracted from A to get B, we simply calculate A - B.

∴ Subtract 3x - 2y + z from x + 2y - 3z

$$\begin{array}{rcccc} x & + & 2y & - & 3z \\ +3x & - & 2y & + & z \\ -\phantom{3x} & + & & - \\ \hline -2x & + & 4y & - & 4z \\ \hline \end{array}$$

∴ The required expression is -2x + 4y - 4z

(ii) What should be subtracted from 2x2 - y2 + 4z2 to get x2 + y2 - z2?

To find what must be subtracted from A to get B, we simply calculate A - B.

∴ Subtract x2 + y2 - z2 from 2x2 - y2 + 4z2

$$\begin{array}{rcccc} 2x^2 & - & y^2 & + & 4z^2 \\ +x^2 & + & y^2 & - & z^2 \\ -\phantom{x^2} & - & & + \\ \hline x^2 & - & 2y^2 & + & 5z^2 \\ \hline \end{array}$$

∴ The required expression is x2 - 2y2 + 5z2

(iii) What should be subtracted from 1 + x - x2 to get 2x + x2?

To find what must be subtracted from A to get B, we simply calculate A - B.

∴ Subtract 2x + x2 from 1 + x - x2

Arranging the expressions in ascending powers (starting with the constant) and use 0 as a placeholder for missing terms.

$$\begin{array}{rcccc} 1 & + & x & - & x^2 \\ +0 & + & 2x & + & x^2 \\ -\phantom{0} & - & & - \\ \hline 1 & - & x & - & 2x^2 \\ \hline \end{array}$$

∴ The required expression is 1 - x - 2x2

8Exercise 13(B)

(i) What should be added to 7a - 9b + 13c to get 9a + b - c?

(ii) What should be added to 1 + 2x - 3x2 to get x2 - x - 1?

(iii) What should be added to m2 - 2mn + 5n2 to get n2 + mn - m2?

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(i) What should be added to 7a - 9b + 13c to get 9a + b - c?

To find what must be added to A to get B, we simply calculate B - A.

∴ Subtract 7a - 9b + 13c from 9a + b - c:

$$\begin{array}{rcccc} 9a & + & b & - & c \\ +7a & - & 9b & + & 13c \\ -\phantom{7a} & + & & - \\ \hline 2a & + & 10b & - & 14c \\ \hline \end{array}$$

∴ The required expression is 2a + 10b - 14c

(ii) What should be added to 1 + 2x - 3x2 to get x2 - x - 1?

To find what must be added to A to get B, we simply calculate B - A.

∴ Subtract 1 + 2x - 3x2 from x2 - x - 1:

Arranging the expressions in descending powers of x (x2, x, constant).

$$\begin{array}{rcccc} x^2 & - & x & - & 1 \\ -3x^2 & + & 2x & + & 1 \\ +\phantom{3x^2} & - & & - \\ \hline 4x^2 & - & 3x & - & 2 \\ \hline \end{array}$$

∴ The required expression is 4x2 - 3x - 2

(iii) What should be added to m2 - 2mn + 5n2 to get n2 + mn - m2?

To find what must be added to A to get B, we simply calculate B - A.

∴ Subtract m2 - 2mn + 5n2 from n2 + mn - m2

Arranging the terms to match (m2, mn, n2):

$$\begin{array}{rcccc} -m^2 & + & mn & + & n^2 \\ +m^2 & - & 2mn & + & 5n^2 \\ -\phantom{m^2} & + & & - \\ \hline -2m^2 & + & 3mn & - & 4n^2 \\ \hline \end{array}$$

∴ The required expression is -2m2 + 3mn - 4n2

9Exercise 13(B)

Find the excess of 4p2 - 2pq + 3q2 over 2p2 - pq + 4q2.

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"Excess" means how much larger the first expression is than the second. To find it, we subtract the second from the first (A - B).

∴ Subtract 2p2 - pq + 4q2 from 4p2 - 2pq + 3q2.

$$\begin{array}{rcccc} 4p^2 & - & 2pq & + & 3q^2 \\ +2p^2 & - & pq & + & 4q^2 \\ -\phantom{2p^2} & + & & - \\ \hline 2p^2 & - & pq & - & q^2 \\ \hline \end{array}$$

Hence, the answer is 2p2 - pq - q2

10Exercise 13(B)

By how much does 3x3 - 5x2 + 2x - 3 exceed 2x3 - 3x2 + x + 1?

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"Exceed" is just another way of asking for the difference. Subtract the second expression from the first.

∴ Subtract 2x3 - 3x2 + x + 1 from 3x3 - 5x2 + 2x - 3

$$\begin{array}{rcccccc} 3x^3 & - & 5x^2 & + & 2x & - & 3 \\ +2x^3 & - & 3x^2 & + & x & + & 1 \\ -\phantom{2x^3} & + & - & - \\ \hline x^3 & - & 2x^2 & + & x & - & 4 \\ \hline \end{array}$$

Hence, the answer is x3 - 2x2 + x - 4

11Exercise 13(B)

How much is -x2 + 7y2 - 3xy less than 2x2 - y2 + xy?

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Here, "how much is A less than B," means B is the larger value. Therefore, we subtract A from B (B - A).

∴ Subtract -x2 + 7y2 - 3xy from 2x2 - y2 + xy

$$\begin{array}{rcc} 2x^2 & - & y^2 & + & xy \\ -x^2 & + & 7y^2 & - & 3xy \\ +\phantom{x^2} & - & & + \\ \hline 3x^2 & - & 8y^2 & + & 4xy \\ \hline \end{array}$$

Hence, the answer is 3x2 - 8y2 + 4xy

12Exercise 13(B)

How much is x3 - 3x2 + 5x - 2 less than 3 - 2x + x2 - x3?

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Here it asks "how much is A less than B," it means B is the larger value. Therefore, we subtract A from B (B - A).

∴ Subtract (x3 - 3x2 + 5x - 2) from (3 - 2x + x2 - x3)

Arranging the expressions in ascending powers of x (constant, x, x2, x3).

$$\begin{array}{rcccccc} 3 & - & 2x & + & x^2 & - & x^3 \\ -2 & + & 5x & - & 3x^2 & + & x^3 \\ +\phantom{2} & - & & + & & - \\ \hline 5 & - & 7x & + & 4x^2 & - & 2x^3 \\ \hline \end{array}$$

Hence, the answer is 5 - 7x + 4x2 - 2x3

13Exercise 13(B)

If x = 2a2 + 3b2 - 5ab, y = b2 - 3a2 + 7ab and z = 6a2 - b2 + ab, find :

(i) x + y - z

(ii) x - y + z

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Given:

x = 2a2 + 3b2 - 5ab

y = b2 - 3a2 + 7ab

z = 6a2 - b2 + ab

(i) x + y - z

First, let's calculate x + y:

Arranging the terms to match (ab, b2, a2):

$$\begin{array}{rcccc} -5ab & + & 3b^2 & + & 2a^2 \\ +7ab & + & b^2 & - & 3a^2 \\ \hline 2ab & + & 4b^2 & - & a^2 \\ \hline \end{array}$$

The sum is 2ab + 4b2 - a2 .

Now, subtract z from the above sum:

$$\begin{array}{rcccc} 2ab & + & 4b^2 & - & a^2 \\ +ab & - & b^2 & + & 6a^2 \\ -\phantom{ab} & + & & - \\ \hline ab & + & 5b^2 & - & 7a^2 \\ \hline \end{array}$$

∴ x + y - z = ab + 5b2 - 7a2

(ii) x - y + z

First, let's calculate x - y:

Arranging the terms to match (a2, b2, ab):

$$\begin{array}{rcccc} 2a^2 & + & 3b^2 & - & 5ab \\ -3a^2 & + & b^2 & + & 7ab \\ +\phantom{3a^2} & - & & - \\ \hline 5a^2 & + & 2b^2 & - & 12ab \\ \hline \end{array}$$

The result is 5a2 + 2b2 - 12ab.

Now, add z to the above result:

$$\begin{array}{rcccc} 5a^2 & + & 2b^2 & - & 12ab \\ +6a^2 & - & b^2 & + & ab \\ \hline 11a^2 & + & b^2 & - & 11ab \\ \hline \end{array}$$

∴ x - y + z = 11a2 + b2 - 11ab

14Exercise 13(B)

The perimeter of a triangle is 8 + 13a + 7a2 and two of its sides are 2a2 + 3a + 2 and 3a2 - 4a - 1. Find the third side of the triangle.

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Given:

Perimeter of a triangle = 8 + 13a + 7a2

Side 1 (S1) = 2a2 + 3a + 2

Side 2 (S2) = 3a2 - 4a - 1

Side 3 (S3) = ?

We know the formula,

Perimeter of a triangle = S1 + S2 + S3

⟹ S3 = Perimeter of a triangle - (S1 + S2)

Substituting the values above, we get:

S3 = (8 + 13a + 7a2) - ((2a2 + 3a + 2) + (3a2 - 4a - 1))

First, let's find S1 + S2:

$$\begin{array}{rcccc} 2 & + & 3a & + & 2a^2 \\ -1 & - & 4a & + & 3a^2 \\ \hline 1 & - & a & + & 5a^2 \\ \hline \end{array}$$

Sum (S1 + S2) = 1 - a + 5a2

Now, we have S3 = (8 + 13a + 7a2) - (1 - a + 5a2)

Subtract Sum (S1 + S2) from perimeter of a triangle:

$$\begin{array}{rcccc} 8 & + & 13a & + & 7a^2 \\ +1 & - & a & + & 5a^2 \\ -\phantom{1} & + & & - \\ \hline 7 & + & 14a & + & 2a^2 \\ \hline \end{array}$$

S3 = 7 + 14a + 2a2

∴ The third side of the triangle is 7 + 14a + 2a2.

15Exercise 13(B)

The perimeter of a rectangle is 16x3 - 6x2 + 12x + 4. If one of its sides is 8x2 + 3x, find the other side.

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Given:

Perimeter of a rectangle = 16x3 - 6x2 + 12x + 4

Length (Known side) = 8x2 + 3x

Breadth = ?

We know the formula,

Perimeter of a rectangle = 2(Length + Breadth)

$\Rightarrow \text {Breadth} = \frac{\text{Perimeter - 2(Length)}}{2}$

Multiply Length by 2:

2(Length) = 2(8x2 + 3x) = 16x2 + 6x

Now, subtract 2(Length) from Perimeter:

$$\begin{array}{rcccccc} 16x^3 & - & 6x^2 & + & 12x & + & 4 \\ +0 & + & 16x^2 & + & 6x & + & 0 \\ -\phantom{0} & - & & - & & - \\ \hline 16x^3 & - & 22x^2 & + & 6x & + & 4 \\ \hline \end{array}$$

Now we have:

Breadth = $\frac{16x^3 - 22x^2 + 6x + 4}{2}$ = 8x3 - 11x2 + 3x + 2

∴ The other side of the rectangle is 8x3 - 11x2 + 3x + 2.

11 Mark · Multiple Choice Questions

Which of the following is a literal?

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A literal is a letter (like x, y, s) used to represent a number.

Here 's' is the literal and remaining are all fixed numerical constants.

Hence, option 3 is the correct option.

21 Mark · Multiple Choice Questions

The coefficient of x in - 6 xyz2 is

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The coefficient is the part of the term other than the chosen variable.

In - 6 xyz2, if we remove the x, we are left with -6yz2.

Hence, option 4 is the correct option.

31 Mark · Multiple Choice Questions

Which of the following is a pair of like terms?

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Like terms must have the exact same variables raised to the exact same powers.

Only option 4 has the same variable part (xy) in both terms.

Hence, option 4 is the correct option.

41 Mark · Multiple Choice Questions

The degree of the polynomial ma2b3 + 6ab2 - m is

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The degree of a term is the sum of the powers of its variables. The degree of the polynomial is the highest degree among its terms.

Term 1 (ma2b3): 1 + 2 + 3 = 6

Term 2 (6ab2): 1 + 2 = 3

Term 3 (m): 1

Here, term 1 has the highest degree i.e., 6

Hence, option 1 is the correct option.

51 Mark · Multiple Choice Questions

The expression -3h4 + 7(h - 1) is a

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Given:

-3h4 + 7(h - 1)

Let's simplify:

-3h4 + 7(h - 1) = -3h4 + 7h - 7

It has three terms: -3h4, 7h and -7. So, it is a trinomial.

Hence, option 3 is the correct option.

61 Mark · Multiple Choice Questions

Which of the following is a binomial?

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A binomial must have exactly two terms after simplification.

Analysis:

  1. a2 - 6b2 + 1000

There are no like terms to combine. It has 3 terms.

  1. -7x2y + xy2 + 3x2y

Let's simplify:

-7x2y + 3x2y + xy2 $\quad$[Grouping like terms]

= (-7 + 3)x2y + xy2

= -4x2y + xy2

It has 2 terms. It is a binomial.

  1. ma2b - (m + n)a2b2 + nab2

There are no like terms to combine. It has 3 terms.

  1. st2 - st + 1

There are no like terms to combine. It has 3 terms.

Hence, option 2 is the correct option.

71 Mark · Multiple Choice Questions

Which of the following is a polynomial?

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In a polynomial, the variables must have whole number exponents (0, 1, 2...). They cannot be in the denominator or under a root.

Analysis:

  1. $1/x$ is x-1 (negative). It is not a polynomial.

  2. $\sqrt{x}$ is x1/2 (fraction). It is not a polynomial.

  3. $\frac{x}{\sqrt{2}} - \frac{1}{\sqrt[3]{2}}$ has a variable with power 1. The root is only on the constant. So, it is a polynomial.

  4. $x^\frac{1}{2} + x^\frac{-1}{2}$ are fractions. It is not a polynomial.

Hence, option 3 is the correct option.

81 Mark · Multiple Choice Questions

Which of the following has the highest degree?

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The highest degree of a polynomial is the greatest sum of the exponents of the variables found in any single term of that expression.

Analysis:

  1. $x^5 + 2x^5 = 3x^5$ → Degree = 5

  2. $2^8$ → Constant, Degree = 0

  3. $a^3b^2c$ → Degree = 3 + 2 + 1 = 6

  4. $\frac{a^6b^5}{a^3b^4} = a^3b^1$ → Degree = 3 + 1 = 4

Among these, $-\frac{3a^3b^2c}{4}$ has the highest degree i.e., 6.

Hence, option 3 is the correct option.

91 Mark · Multiple Choice Questions

The value of the expression 2m2 + 3n2m + $\frac{7}{2}n^2 + 8$, when m = -2 and n = 2 is

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Given expression = 2m2 + 3n2m + $\frac{7}{2}n^2 + 8$

m = -2, n = 2

Substituting the given values in the expression, we get:

= 2(-2)2 + 3(2)2(-2) + $\frac{7}{2}(2)^2 + 8$

= 2(4) + 3(4)(-2) + $\frac{7}{2}(4) + 8$

= 8 + (-24) + $\frac{28}{2} + 8$

= 8 - 24 + 14 + 8

= 6

Hence, option 3 is the correct option.

101 Mark · Multiple Choice Questions

The sum of the polynomials bn - 8am - 8cp, 5cp - am + 2bn and 6am + 5bn - 3cp is equal to

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Given polynomials = bn - 8am - 8cp, 5cp - am + 2bn and 6am + 5bn - 3cp

Arranging the expressions so that am is under am, bn is under bn and cp is under cp.

$$\begin{array}{rccc} -8am & + & bn & - & 8cp \\ -\phantom{8} am & + & 2bn & + & 5cp \\ +6am & + & 5bn & - & 3cp \\ \hline -3am & + & 8bn & - & 6cp \\ \hline \end{array}$$

Sum is -3am + 8bn - 6cp

Hence, option 4 is the correct option.

1Mental Maths

Fill in the blanks :

(i) The highest power of the ............... in a polynomial is called its degree.

(ii) The degree of the polynomial 75 is ............... .

(iii) Several parts of an algebraic expression separated by + or - signs are called the ............... of the expression.

(iv) Any number is a polynomial of degree ............... .

(v) Terms having the same ............... are called like terms.

(vi) The algebraic expression for the statement ‘the number of times b is contained in x' is ............... .

(vii) 1 + x + y + xy is a polynomial having ............... terms and degree .............. .

(viii) The length of a side of a square having perimeter 8x2 - 2y + 16xy is ............... .

(ix) In a polynomial, the exponents of the variables are always ............... .

(x) If the length of a rectangle having perimeter (6 m2 - 2 mn + 2 m2n - 4n2) units, is (3m2 + m2n - 2 mn) units, then its breadth is equal to ............... units.

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(i) The highest power of the variable in a polynomial is called its degree.

(ii) The degree of the polynomial 75 is 0.

(iii) Several parts of an algebraic expression separated by + or - signs are called the terms of the expression.

(iv) Any number is a polynomial of degree 0.

(v) Terms having the same literal coefficients are called like terms.

(vi) The algebraic expression for the statement ‘the number of times b is contained in x' is $\frac{x}{b}$.

(vii) 1 + x + y + xy is a polynomial having 4 terms and degree 2.

(viii) The length of a side of a square having perimeter 8x2 - 2y + 16xy is $2x^2 - \frac{1}{2}y + 4xy$.

(ix) In a polynomial, the exponents of the variables are always non-negative integers.

(x) If the length of a rectangle having perimeter (6 m2 - 2 mn + 2 m2n - 4n2) units, is (3m2 + m2n - 2 mn) units, then its breadth is equal to mn - 2n2 units.

Explanation

(i) In algebra, the degree represents the maximum power of the variable present. For example, in x3 + x, the degree is 3.

(ii) The degree refers to the power of the variable. Since 75 is just a constant with no variable, its degree is 0.

(iii) Terms are the individual building blocks of an expression. In 3x + 5y, "3x" and "5y" are the terms.

(iv) Any constant number k can be written as k.x0. Since the variable power is 0, the degree is 0.

(v) Like terms must have the exact same variables raised to the exact same powers, such as 5ab2 and -2ab2.

(vi) To find how many times one number is "contained" in another, we use division. For example, 2 is contained in 10 five times (10 ÷ 2).

(vii) Given polynomial: 1 + x + y + xy

Terms: 1, x, y, xy = 4 terms

Degree: The term xy has degree 1 + 1 = 2.

(viii)

Given:

Perimeter of square = 8x2 - 2y + 16xy

Side = ?

We have the formula:

Perimeter of a square = 4 x (Side)

$\Rightarrow \text {Side} = \frac{\text{Perimeter}}{4}$

Substituting the values above, we get:

$\text {Side} = \frac{8x^2 - 2y + 16xy}{4} = 2x^2 - \frac{1}{2}y + 4xy$

(ix) Polynomials are defined by having non-negative integer exponents. They cannot have variables with negative powers (x-1) or roots ($\sqrt{x}$).

(x)

Given:

Length = (3m2 + m2n - 2 mn)

Perimeter of a rectangle = (6 m2 - 2 mn + 2 m2n - 4n2)

Breadth = ?

We know the formula:

Perimeter of a rectangle = 2(Length + Breadth)

$\Rightarrow \text {Breadth} = \frac{\text{Perimeter - 2(Length)}}{2}$

First, find 2 x Length:

2(Length) = 2(3m2 + m2n - 2 mn) = 6m2 + 2m2n - 4 mn

Now, find Perimeter - 2(Length):

$$\begin{array}{rcccccc} 6m^2 & + & 2m^2n & - & 2mn & - & 4n^2 \\ -6m^2 & + & 2m^2n & - & 4mn & + & 0 \\ -\phantom{6m^2} & - & & + & & - \\ \hline 0 & & 0 & & 2mn & - & 4n^2 \\ \hline \end{array}$$

Perimeter - 2(Length) = 2mn - 4n2

Now, we have:

Breadth = $\frac{2mn - 4n^2}{2}$

Breadth = mn - 2n2

2Mental Maths

Write true (T) or false (F) :

(i) A literal can take on various numerical values.

(ii) 2a3b - a2b - 3a2b2 + 7ba2 - ba3 is a trinomial.

(iii) 3mn is a factor of -9mn2.

(iv) If we add a monomial and a trinomial, the answer can be a monomial.

(v) The coefficient of a2b in - 9a2b2c is -9bc.

(vi) The degree of the monomial 33 is 3.

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(i) True
Reason — A literal is a letter (like x, a, or b) used in algebra to represent a variable quantity. Unlike a constant (like 5), which has a fixed value, a literal can represent various numerical values depending on the problem or context.

(ii) True
Reason —

Given expression:

2a3b - a2b - 3a2b2 + 7ba2 - ba3

= (2a3b - ba3) + (- a2b + 7ba2) - 3a2b2 $\quad$[Arranging like terms together]

= (2-1)a3b + (-1 + 7)a2b - 3a2b2 $\quad$[Combining coefficients]

= a3b + 6a2b - 3a2b2

Since the simplified expression has exactly 3 terms, it is a trinomial.

(iii) True
Reason — A term is a factor if it divides the other term completely without leaving a remainder.

$\frac{-9mn^2}{3mn} = \frac{-9}{3} \times \frac{m}{m} \times \frac{n^2}{n} = -3n$

Since 3mn x (-3n) = -9mn2, it is a factor.

(iv) False
Reason — Usually, when we add a monomial (1 term) to a trinomial (3 terms), the maximum number of terms we can get is 4, and the minimum is 2 (if the monomial is a like term that combines with one of the trinomial's terms).

Example:

Add monomial (2x) and trinomial (x2 + 3x + 5):

2x + (x2 + 3x + 5) = x2 + 5x + 5

The result is a trinomial, not a monomial.

(v) True
Reason — To find the coefficient of a2b in the term -9a2b2c, we remove a2b from the term:

$\frac{-9a^2b^2c}{a^2b} = -9bc$

(vi) False
Reason — The degree of a polynomial is determined by the power of the variables. Since 33 is a constant number and has no variable attached to it, its degree is 0.

1Case Study Based Questions

Saket wrote four different algebraic expressions in his notebook. These are $f(x) = 2x^3 - \frac{1}{3}x,\ g(x) = x - \frac{1}{x} + 2,\ h(x) = x^2 - 2\sqrt{x}\ \text{and}\ k(y) = 2y - 1$.

(1) Which of these expressions is/are binomials ?

  1. f(x), g(x), h(x) only
  2. f(x), g(x), k(y) only
  3. f(x), h(x), k(y) only
  4. f(x), h(x) only

(2) Which of these expressions is/are not polynomials ?

  1. f(x), g(x), h(x) only
  2. f(x), h(x) only
  3. g(x), h(x) only
  4. h(x) only

(3) Which of these expressions is/are polynomials in two variables ?

  1. f(x) only
  2. k(y) only
  3. f(x), k(y) only
  4. None of these

(4) The degree of the polynomial f (x) is :

Show SolutionHide Solution↓

Given:

$f(x) = 2x^3 - \frac{1}{3}x$

$g(x) = x - \frac{1}{x} + 2$

$h(x) = x^2 - 2\sqrt{x}$

k(y) = 2y - 1

(1)

f(x): 2 terms (2x3 and $-\frac{1}{3}x$) → Binomial.

g(x): 3 terms (x, $-\frac{1}{x}$, and $2$) → Trinomial.

h(x): 2 terms (x2 and $-2\sqrt{x}$) → Binomial.

k(y): 2 terms (2y and -1) → Binomial.

Binomial expressions are f(x), h(x), k(y).

Hence, option 3 is the correct option.

(2) A polynomial cannot have variables in the denominator or under a root (fractional powers).

Analysis:

$f(x) = 2x^3 - \frac{1}{3}x$

The powers of x are 3 and 1. Both are whole numbers. It is a polynomial.

$g(x) = x - \frac{1}{x} + 2$

The term $-\frac{1}{x}$ can be written as -x-1, the exponent -1 which is a negative integer not a whole number. So, it is not a polynomial.

$h(x) = x^2 - 2\sqrt{x}$

The term $-2\sqrt{x}$ can be written as -2x1/2, the exponent $\frac{1}{2}$ is a fraction, not a whole number. So, it is not a polynomial.

k(y) = 2y - 1

The power of y is 1, which is a whole number. So, it is a polynomial.

So, g(x) and h(x) are not polynomials.

Hence, option 3 is the correct option.

(3) A "polynomial in two variables" must contain exactly two different letters (like x and y, or a and b) throughout its terms.

Analysis:

$f(x) = 2x^3 - \frac{1}{3}x$

Only x appears in both terms. This is a polynomial in one variable (x).

$g(x) = x - \frac{1}{x} + 2$

Only x appears. This is an algebraic expression in one variable (x). It is not a polynomial.

$h(x) = x^2 - 2\sqrt{x}$

Only x appears. This is an algebraic expression in one variable (x). It is not a polynomial.

k(y) = 2y - 1

Only y appears. This is a polynomial in one variable (y).

No expression is a polynomial in two variables.

Hence, option 4 is the correct option.

(4) $f(x) = 2x^3 - \frac{1}{3}x$

The highest power of x in $2x^3 - \frac{1}{3}x$ is 3.

Hence, option 4 is the correct option.

2Case Study Based Questions

Vasu has a rectangular farmland A. The length of this farmland is x2y - 2xy + 3x2 and its perimeter is 2x2y + 6x2 - 2xy - 4y2. Today he purchased the adjacent farmland B and combined the two farmlands into one. The length of his farmland now increased by x2 + xy, while the breadth remained the same.

Vasu has a rectangular farmland A. The length of this farmland is x. R.S. Aggarwal Mathematics Solutions ICSE Class 7.

(1) Find the breadth of farmland A :

  1. x2y + 3x2 - 4y2
  2. xy - 2y2
  3. 12x2 - 4xy
  4. 6x2 + xy - 2y2

(2) Find the length of the combined farmland owned by Vasu :

  1. x2 + 2xy - 2y2
  2. 4x2 - 3xy + x2y
  3. 4x2 - xy + x2y
  4. 2x2 - 3xy + x2y

(3) The perimeter of Vasu's combined farmland is :

  1. 8x2 + 2x2y - 4y2
  2. 4y2 + 4xy + 2x2y + 8x2
  3. 4x2 - 2x2y + 4y2
  4. 4x2 + 4xy - 2x2y - 8x2

(4) The change in the perimeter after combining farmlands A and B is :

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Given for Farmland A:

Length (LA) = x2y - 2xy + 3x2

Perimeter (PA) = 2x2y + 6x2 - 2xy - 4y2

(1)

We know the formula:

Perimeter of a rectangle = 2(Length + Breadth)

$\Rightarrow \text {Breadth} = \frac{\text{Perimeter - 2(Length)}}{2}$

First, find 2(Length):

2(Length) = 2(x2y - 2xy + 3x2) = 2x2y - 4xy + 6x2

Now, calculate Perimeter - 2(Length):

$$\begin{array}{rcccccc} 2x^2y & + & 6x^2 & - & 2xy & - & 4y^2 \\ +2x^2y & + & 6x^2 & - & 4xy & + & 0 \\ -\phantom{2x^2y} & - & & + & & - \\ \hline 0 & & 0 & & 2xy & - & 4y^2 \\ \hline \end{array}$$

Perimeter - 2(Length) = 2xy - 4y2

Now we have:

Breadth = $\frac{2xy - 4y^2}{2}$

Breadth = xy - 2y2

Hence, option 2 is the correct option.

(2)

Original Length (LA) = x2y - 2xy + 3x2

Increase = x2 + xy

Combined Length = Original Length + Increase

Substituting the values above, we get:

Combined Length = (x2y - 2xy + 3x2) + (x2 + xy)

= (3x2 + x2) + (- 2xy + xy) + x2y $\quad$[Arranging like terms together]

= (3 + 1)x2 + (-1)xy + x2y

= 4x2 - xy + x2y

Hence, option 3 is the correct option.

(3)

Combined Length = 4x2 - xy + x2y $\quad$[From step 2]

Breadth = xy - 2y2 $\quad$[From step 1]

Perimeter of combined farmland = ?

Let's apply the perimeter of a rectangle formula:

Perimeter of combined farmland = 2(Length + Breadth)

Let's first calculate Length + Breadth.

We have:

Length + Breadth = (4x2 - xy + x2y) + (xy - 2y2)

= 4x2 + (- xy + xy) + x2y + (- 2y2) $\quad$[Arranging like terms together]

= 4x2 + 0xy + x2y - 2y2

= 4x2 + x2y - 2y2

Now we have:

Perimeter of combined farmland = 2 x (4x2 + x2y - 2y2) = 8x2 + 2x2y - 4y2

Hence, option 1 is the correct option.

(4)

Original Perimeter = 2x2y + 6x2 - 2xy - 4y2

Combined Perimeter = 8x2 + 2x2y - 4y2

Change in perimeter = Combined Perimeter - Original Perimeter

Substituting the values above, we get:

Change in perimeter = (8x2 + 2x2y - 4y2) - (2x2y + 6x2 - 2xy - 4y2)

= 8x2 + 2x2y - 4y2 - 2x2y - 6x2 + 2xy + 4y2 $\quad$[Simplifying brackets]

= (8x2 - 6x2) + (2x2y - 2x2y) + 2xy + (- 4y2 + 4y2) $\quad$[Arranging like terms together]

= 2x2 + 0x2y + 2xy + 0y2

= 2x2 + 2xy

Hence, option 4 is the correct option.

1Assertions and Reasons

Assertion: The expression x + y - 2x is a trinomial.

Reason: An algebraic expression containing three terms is called a trinomial.

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Assertion (A) is false but Reason (R) is true.

Explanation

Given expression:

x + y - 2x

Let's simplify it:

∴ x + y - 2x = (x - 2x) + y $\quad$[Arranging like terms together]

= -x + y

= y - x

∴ Simplified expression is y - x, which has only two terms. Therefore, it is a binomial, not a trinomial. So, Assertion is incorrect.

Reason is true because it is the correct definition of a trinomial.

Hence, option 4 is the correct option.

2Assertions and Reasons

Assertion: If we subtract 15x2 - 9x + 1 from 1, then we get -15x2 + 9x.

Reason: The degree of 15x2 - 9x + 1 is 3 as it has three terms and degree of -15x2 + 9x is 2 as it has two terms.

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Assertion (A) is true but Reason (R) is false.

Explanation

Assertion:

Subtracting 15x2 - 9x + 1 from 1:

1 - (15x2 - 9x + 1)

= 1 - 15x2 + 9x - 1 $\quad$[Simplifying brackets]

= (1 - 1) - 15x2 + 9x

= 0 - 15x2 + 9x

= - 15x2 + 9x

The result matches the statement exactly.

So, Assertion is true.

Reason is false because, the degree of a polynomial is determined by the highest power of the variable, not by the number of terms.

Degree of 15x2 - 9x + 1 = 2 (because the highest power of x is 2).

Degree of -15x2 + 9x = 2 (because the highest power of x is 2).

The Reason incorrectly claims the degree is 3 based on the number of terms.

Hence, option 3 is the correct option.

1Competency Focused Questions

Consider the expression. "5 subtracted from the sum of 5 times u squared and 5 times the product of u and −1". Which of these statements is correct?

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Let's translate the statement into an algebraic expression step-by-step:

Step 1: "5 times u squared" = 5u2

Step 2: "the product of u and −1" = u × (−1) = −u

Step 3: "5 times the product of u and −1" = 5 × (−u) = −5u

Step 4: "the sum of 5 times u squared and 5 times the product of u and −1" = 5u2 + (−5u) = 5u2 − 5u

Step 5: "5 subtracted from the sum..." = (5u2 − 5u) − 5 = 5u2 − 5u − 5

So, the expression is 5u2 − 5u − 5.

Now, let's analyse each option:

1. All terms of the expression are 5u2, −5u and −5.
The expression 5u2 − 5u − 5 has three terms separated by '−' signs, namely 5u2, −5u and −5. This statement is correct.

2. All terms of the expression are 5u2 and −5u.
This statement misses the constant term −5. So, it is incorrect.

3. All factors of the term −5u are 5 and u.
The term −5u = (−5) × u. The factors of −5u are −5 and u, not 5 and u. So, this statement is incorrect.

4. All factors of the term 5u2 are 5 and u.
The term 5u2 = 5 × u × u. The factors of 5u2 are 5, u and u2. The statement misses u2. So, it is incorrect.

Hence, option 1 is the correct option.

2Competency Focused Questions

Study the following statements and select the correct option.

P: The number of unlike terms in 4pq2 − 2q2r + q2p + 3pqr + q2r − 8 is 4.

Q: An expression having three or more terms is called a trinomial.

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Checking Statement P:

Given expression:

4pq2 − 2q2r + q2p + 3pqr + q2r − 8

Let's group like terms together (recall pq2 = q2p):

= (4pq2 + q2p) + (−2q2r + q2r) + 3pqr − 8 $\quad$[Arranging like terms together]

= (4 + 1)pq2 + (−2 + 1)q2r + 3pqr − 8 $\quad$[Combining coefficients]

= 5pq2 − q2r + 3pqr − 8

The simplified expression has 4 unlike terms: 5pq2, −q2r, 3pqr and −8.

∴ Statement P is true.

Checking Statement Q:

A trinomial is an algebraic expression containing exactly 3 terms, not three or more.

An expression containing more than one term is called a multinomial.

∴ Statement Q is false.

So, P is true but Q is false.

Hence, option 3 is the correct option.

3Competency Focused Questions

The cost of entry tickets to an amusement park are different for men and children. A man's ticket costs ₹800 and a child's ticket costs ₹500.

On Monday, the number of men who visited the amusement park was the square of the number of children who visited. How much money was collected by selling entry tickets on Monday?

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Given:

Cost of a man's ticket = ₹800

Cost of a child's ticket = ₹500

Let the number of children who visited the amusement park = x

According to the question, the number of men = (number of children)2 = x2

Money collected from men's tickets = Cost per man × Number of men

= ₹800 × x2

= ₹800x2

Money collected from children's tickets = Cost per child × Number of children

= ₹500 × x

= ₹500x

Total money collected = Money from men + Money from children

= ₹(800x2 + 500x)

Hence, option 2 is the correct option.

4Competency Focused Questions

Sonika and Komal are collecting some marbles for their project. Sonika collected 15 red marbles and 6x blue marbles, whereas Komal collected 5y red marbles and 8x blue marbles. After some time Sonika loses 3y marbles and Komal collected 8 more marbles. How many total number of marbles they both have now, if x = 2 and y = 3?

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Marbles with Sonika:

Initially Sonika had = 15 red marbles + 6x blue marbles = (15 + 6x) marbles

After losing 3y marbles, Sonika has = (15 + 6x) − 3y = 15 + 6x − 3y marbles

Marbles with Komal:

Initially Komal had = 5y red marbles + 8x blue marbles = (5y + 8x) marbles

After collecting 8 more marbles, Komal has = (5y + 8x) + 8 = 5y + 8x + 8 marbles

Total marbles with both:

Total = (15 + 6x − 3y) + (5y + 8x + 8)

= (6x + 8x) + (−3y + 5y) + (15 + 8) $\quad$[Arranging like terms together]

= 14x + 2y + 23

Substituting x = 2 and y = 3, we get:

Total = 14(2) + 2(3) + 23

= 28 + 6 + 23

= 57

Hence, option 3 is the correct option.

5Competency Focused Questions

What is sum of the numerical coefficients of the variables m and n in the expression given by the statement? "Circumference of the circle of radius m subtracted from the circumference of the circle of radius $\frac{n}{2}$".

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We know the formula:

Circumference of a circle = 2πr, where r is the radius.

Circumference of a circle of radius m = 2πm

Circumference of a circle of radius $\frac{n}{2}$ = $2\pi \times \frac{n}{2}$ = πn

According to the question, circumference of the circle of radius m is subtracted from the circumference of the circle of radius $\frac{n}{2}$:

Required expression = πn − 2πm

In this expression:

Numerical coefficient of m = −2π

Numerical coefficient of n = π

Sum of the numerical coefficients = −2π + π = −π

Hence, option 1 is the correct option.

6Competency Focused Questions

Which of the following statement is true about the expression given below?

−14m2l − 17m2 + 4n2 − 15lm2 − (−6m2 − 10n2 + 18l2m2) − 12m2l2

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Given expression:

−14m2l − 17m2 + 4n2 − 15lm2 − (−6m2 − 10n2 + 18l2m2) − 12m2l2

First, let's open the bracket by changing the sign of each term inside:

= −14m2l − 17m2 + 4n2 − 15lm2 + 6m2 + 10n2 − 18l2m2 − 12m2l2

Now, group the like terms together (recall m2l = lm2 and l2m2 = m2l2):

= (−14m2l − 15lm2) + (−17m2 + 6m2) + (4n2 + 10n2) + (−18l2m2 − 12m2l2)

= (−14 − 15)m2l + (−17 + 6)m2 + (4 + 10)n2 + (−18 − 12)l2m2 $\quad$[Combining coefficients]

= −29m2l − 11m2 + 14n2 − 30l2m2

The simplified expression has 4 terms, so it is a polynomial (not a trinomial).

Hence, option 4 is the correct option.

Press ↓ to reveal a solution and move to the next question. Back to Solutions for Class 7 RS Aggarwal ICSE Foundation Mathematics.