ICSE Class 6 Mathematics · Solutions for Class 6 RS Aggarwal ICSE Foundation Mathematics · 52 solved questions
Write each of the following decimals in figures:
(i) Seventy three point eight four.
(ii) Three hundred forty six point zero nine five.
(iii) Five hundred eight point two six.
(iv) Nineteen point six one eight.
(v) Zero point seven nine three.
(vi) Ten point zero zero seven.
(i) 73.84
(ii) 346.095
(iii) 508.26
(iv) 19.618
(v) 0.793
(vi) 10.007
Write the place value of each digit in each of the following decimals:
(i) 46.38
(ii) 57.095
(iii) 132.405
(iv) 19.006
(i) We can arrange the digits of 46.38 in the place value chart, as shown below:
| Tens | Ones | Decimal point | Tenths | Hundredths |
|---|---|---|---|---|
| 4 | 6 | . | 3 | 8 |
The place value of each digit is given below:
| Digit | 4 | 6 | 3 | 8 |
|---|---|---|---|---|
| Place Value | 40 | 6 | $\frac{3}{10}$ | $\frac{8}{100}$ |
(ii) We can arrange the digits of 57.095 in the place value chart, as shown below:
| Tens | Ones | Decimal point | Tenths | Hundredths | Thousandths |
|---|---|---|---|---|---|
| 5 | 7 | . | 0 | 9 | 5 |
The place value of each digit is given below:
| Digit | 5 | 7 | 0 | 9 | 5 |
|---|---|---|---|---|---|
| Place Value | 50 | 7 | 0 | $\frac{9}{100}$ | $\frac{5}{1000}$ |
(iii) We can arrange the digits of 132.405 in the place value chart, as shown below:
| Hundreds | Tens | Ones | Decimal point | Tenths | Hundredths | Thousandths |
|---|---|---|---|---|---|---|
| 1 | 3 | 2 | . | 4 | 0 | 5 |
The place value of each digit is given below:
| Digit | 1 | 3 | 2 | 4 | 0 | 5 |
|---|---|---|---|---|---|---|
| Place Value | 100 | 30 | 2 | $\frac{4}{10}$ | 0 | $\frac{5}{1000}$ |
(iv) We can arrange the digits of 19.006 in the place value chart, as shown below:
| Tens | Ones | Decimal point | Tenths | Hundredths | Thousandths |
|---|---|---|---|---|---|
| 1 | 9 | . | 0 | 0 | 6 |
The place value of each digit is given below:
| Digit | 1 | 9 | 0 | 0 | 6 |
|---|---|---|---|---|---|
| Place Value | 10 | 9 | 0 | 0 | $\frac{6}{1000}$ |
Write each of the following decimals in expanded form:
(i) 53.48
(ii) 6.927
(iii) 10.084
(iv) 8.005
(v) 274.503
(vi) 31.02
(vii) 1635.72
(i) We have,
$$\begin{aligned}53.48 = 5 \times 10 + 3 \times 1 + 4 \times \frac{1}{10} + 8 \times \frac{1}{100} \\[1em] = 50 + 3 + \frac{4}{10} + \frac{8}{100}\end{aligned}$$
(ii) We have,
$$\begin{aligned}6.927 = 6 \times 1 + 9 \times \frac{1}{10} + 2 \times \frac{1}{100} + 7 \times \frac{1}{1000} \\[1em] = 6 + \frac{9}{10} + \frac{2}{100} + \frac{7}{1000}\end{aligned}$$
(iii) We have,
$$\begin{aligned}10.084 = 1 \times 10 + 0 \times 1 + 0 \times \frac{1}{10} + 8 \times \frac{1}{100} + 4 \times \frac{1}{1000} \\[1em] = 10 + \frac{8}{100} + \frac{4}{1000}\end{aligned}$$
(iv) We have,
$$\begin{aligned}8.005 = 8 \times 1 + 0 \times \frac{1}{10} + 0 \times \frac{1}{100} + 5 \times \frac{1}{1000} \\[1em] = 8 + \frac{5}{1000}\end{aligned}$$
(v) We have,
$$\begin{aligned}274.503 = 2 \times 100 + 7 \times 10 + 4 \times 1 + 5 \times \frac{1}{10} + 0 \times \frac{1}{100} + 3 \times \frac{1}{1000} \\[1em] = 200 + 70 + 4 + \frac{5}{10} + \frac{3}{1000}\end{aligned}$$
(vi) We have,
$$\begin{aligned}31.02 = 3 \times 10 + 1 \times 1 + 0 \times \frac{1}{10} + 2 \times \frac{1}{100} \\[1em] = 30 + 1 + \frac{2}{100}\end{aligned}$$
(vii) We have,
$$\begin{aligned}1635.72 = 1 \times 1000 + 6 \times 100 + 3 \times 10 + 5 \times 1 + 7 \times \frac{1}{10} + 2 \times \frac{1}{100} \\[1em] = 1000 + 600 + 30 + 5 + \frac{7}{10} + \frac{2}{100}\end{aligned}$$
Write each of the following as a decimal number:
(i) 60 + 8 + $\frac{4}{10} + \frac{5}{100}$
(ii) 500 + 4 + $\frac{6}{10} + \frac{8}{100} + \frac{3}{1000}$
(iii) 300 + 20 + $\frac{1}{10} + \frac{6}{1000}$
(iv) 2000 + 80 + $\frac{4}{100} + \frac{8}{1000}$
(v) 6000 + 3 + $\frac{2}{10} + \frac{7}{1000}$
(i) We have,
$$\begin{aligned}60 + 8 + \frac{4}{10} + \frac{5}{100} \\[1em] = 6 \times 10 + 8 \times 1 + 4 \times \frac{1}{10} + 5 \times \frac{1}{100} \\[1em] = 68.45\end{aligned}$$
(ii) We have,
$$\begin{aligned}500 + 4 + \frac{6}{10} + \frac{8}{100} + \frac{3}{1000} \\[1em] = 5 \times 100 + 0 \times 10 + 4 \times 1 + 6 \times \frac{1}{10} + 8 \times \frac{1}{100} + 3 \times \frac{1}{1000} \\[1em] = 504.683\end{aligned}$$
(iii) We have,
$$\begin{aligned}300 + 20 + \frac{1}{10} + \frac{6}{1000} \\[1em] = 3 \times 100 + 2 \times 10 + 0 \times 1 + 1 \times \frac{1}{10} + 0 \times \frac{1}{100} + 6 \times \frac{1}{1000} \\[1em] = 320.106\end{aligned}$$
(iv) We have,
$$\begin{aligned}2000 + 80 + \frac{4}{100} + \frac{8}{1000} \\[1em] = 2 \times 1000 + 0 \times 100 + 8 \times 10 + 0 \times 1 + 0 \times \frac{1}{10} + 4 \times \frac{1}{100} + 8 \times \frac{1}{1000} \\[1em] = 2080.048\end{aligned}$$
(v) We have,
$$\begin{aligned}6000 + 3 + \frac{2}{10} + \frac{7}{1000} \\[1em] = 6 \times 1000 + 0 \times 100 + 0 \times 10 + 3 \times 1 + 2 \times \frac{1}{10} + 0 \times \frac{1}{100} + 7 \times \frac{1}{1000} \\[1em] = 6003.207\end{aligned}$$
Write each of the following numerals as decimals:
(i) $2\frac{7}{10}$
(ii) $43\frac{3}{10}$
(iii) $6\frac{15}{100}$
(iv) $18\frac{9}{100}$
(v) $5\frac{123}{1000}$
(vi) $4\frac{37}{1000}$
(vii) $10\frac{8}{1000}$
(i) We have,
$2\frac{7}{10}=2+\frac{7}{10}=2+0.7=2.7$
Hence, the decimal form is 2.7.
(ii) We have,
$43\frac{3}{10}=43+\frac{3}{10}=43+0.3=43.3$
Hence, the decimal form is 43.3.
(iii) We have,
$6\frac{15}{100}=6+\frac{15}{100}=6+0.15=6.15$
Hence, the decimal form is 6.15.
(iv) We have,
$18\frac{9}{100}=18+\frac{9}{100}=18+0.09=18.09$
Hence, the decimal form is 18.09.
(v) We have,
$5\frac{123}{1000}=5+\frac{123}{1000}=5+0.123=5.123$
Hence, the decimal form is 5.123.
(vi) We have,
$4\frac{37}{1000}=4+\frac{37}{1000}=4+0.037=4.037$
Hence, the decimal form is 4.037.
(vii) We have,
$10\frac{8}{1000}=10+\frac{8}{1000}=10+0.008=10.008$
Hence, the decimal form is 10.008.
Convert each of the sets of unlike decimals into like decimals:
(i) 9.4, 65.83, 0.065
(ii) 0.5, 7.573, 4.26, 8.4
(iii) 1.2, 0.06, 3.5, 6.38
(iv) 2.8, 16.85, 64.056, 143.625
(i) Maximum number of decimal places in the given numbers is 3. So, we can convert each of the decimals into one having 3 decimal places by annexing zeros.
9.4 = 9.400
65.83 = 65.830
0.065 = 0.065
As 9.400, 65.830, 0.065 have equal number of decimal places, they are like decimals.
(ii) Maximum number of decimal places in the given numbers is 3. So, we can convert each of the decimals into one having 3 decimal places by annexing zeros.
0.5 = 0.500
7.573 = 7.573
4.26 = 4.260
8.4 = 8.400
As 0.500, 7.573, 4.260, 8.400 have equal number of decimal places, they are like decimals.
(iii) Maximum number of decimal places in the given numbers is 2. So, we can convert each of the decimals into one having 2 decimal places by annexing zeros.
1.2 = 1.20
0.06 = 0.06
3.5 = 3.50
6.38 = 6.38
As 1.20, 0.06, 3.50, 6.38 have equal number of decimal places, they are like decimals.
(iv) Maximum number of decimal places in the given numbers is 3. So, we can convert each of the decimals into one having 3 decimal places by annexing zeros.
2.8 = 2.800
16.85 = 16.850
64.056 = 64.056
143.625 = 143.625
As 2.800, 16.850, 64.056, 143.625 have equal number of decimal places, they are like decimals.
Fill in the placeholders with > or <:
(i) 63.4 ${\boxed{\phantom{63}}}$ 36.85
(ii) 4.805 ${\boxed{\phantom{63}}}$ 4.85
(iii) 8.23 ${\boxed{\phantom{63}}}$ 8.32
(iv) 5.06 ${\boxed{\phantom{63}}}$ 5.006
(v) 7.86 ${\boxed{\phantom{63}}}$ 7.806
(vi) 0.98 ${\boxed{\phantom{63}}}$ 1
(i) The given decimals are 63.4 and 36.85. Comparing their whole number parts clearly shows that, 63 > 36.
Therefore, 63.4 > 36.85.
(ii) The given decimals are 4.805 and 4.85.
Writing them as like decimals: 4.805 and 4.850.
Comparing the decimal parts, we find that 805 < 850.
Therefore, 4.805 < 4.85.
(iii) The given decimals are 8.23 and 8.32. Their whole number parts are equal. Comparing their tenths digits, 2 < 3.
Therefore, 8.23 < 8.32.
(iv) The given decimals are 5.06 and 5.006.
Writing them as like decimals: 5.060 and 5.006.
Comparing the decimal parts, 60 > 6.
Therefore, 5.06 > 5.006.
(v) The given decimals are 7.86 and 7.806.
Writing them as like decimals: 7.860 and 7.806.
Comparing the decimal parts, 860 > 806.
Therefore, 7.86 > 7.806.
(vi) The given decimals are 0.98 and 1.
Comparing their whole number parts, 0 < 1.
Therefore, 0.98 < 1.
Arrange the following decimals in ascending order:
(i) 3.6, 4.2, 3.57, 4.18, 3.06, 4.08
(ii) 5.37, 3.57, 3.5, 5.3, 5.7, 3.07
(iii) 0.7, 0.007, 0.07, 7.7, 7.07, 0.77
(iv) 2.2, 2.02, 0.22, 0.02, 0.202, 2.002
(v) 76.8, 68.7, 86.7, 87.6, 78.6, 7.86
(i) The maximum number of decimal places in the given decimals is 2. So, we convert each of the given decimals into like decimals having two decimal places by annexing zeros.
The decimals are: 3.60, 4.20, 3.57, 4.18, 3.06, 4.08
Clearly, 3.06 < 3.57 < 3.60 < 4.08 < 4.18 < 4.20.
Hence, the given decimals in ascending order are:
3.06 < 3.57 < 3.6 < 4.08 < 4.18 < 4.2.
(ii) The maximum number of decimal places in the given decimals is 2. So, we convert each of the given decimals into like decimals having two decimal places by annexing zeros.
The decimals are: 5.37, 3.57, 3.50, 5.30, 5.70, 3.07
Clearly, 3.07 < 3.50 < 3.57 < 5.30 < 5.37 < 5.70.
Hence, the given decimals in ascending order are:
3.07 < 3.5 < 3.57 < 5.3 < 5.37 < 5.7.
(iii) The maximum number of decimal places in the given decimals is 3. So, we convert each of the given decimals into like decimals having three decimal places by annexing zeros.
The decimals are: 0.700, 0.007, 0.070, 7.700, 7.070, 0.770
Clearly, 0.007 < 0.070 < 0.700 < 0.770 < 7.070 < 7.700.
Hence, the given decimals in ascending order are:
0.007 < 0.07 < 0.7 < 0.77 < 7.07 < 7.7
(iv) The maximum number of decimal places in the given decimals is 3. So, we convert each of the given decimals into like decimals having three decimal places by annexing zeros.
The decimals are: 2.200, 2.020, 0.220, 0.020, 0.202, 2.002
Clearly, 0.020 < 0.202 < 0.220 < 2.002 < 2.020 < 2.200.
Hence, the given decimals in ascending order are:
0.02 < 0.202 < 0.22 < 2.002 < 2.02 < 2.2
(v) The maximum number of decimal places in the given decimals is 2. So, we convert each of the given decimals into like decimals having two decimal places by annexing zeros.
The decimals are: 76.80, 68.70, 86.70, 87.60, 78.60, 7.86
Clearly, 7.86 < 68.70 < 76.80 < 78.60 < 86.70 < 87.60.
Hence, the given decimals in ascending order are:
7.86 < 68.7 < 76.8 < 78.6 < 86.7 < 87.6
Arrange the following decimals in descending order:
(i) 6.6, 0.06, 0.6, 0.006, 6.66
(ii) 3.3, 3.03, 0.33, 33.3, 0.303, 30.3
(iii) 2.9, 3.6, 9.2, 6.3, 3.06, 6.03
(iv) 77.7, 0.7, 7.7, 0.07, 7.07, 7.77
(v) 7.35, 3.75, 5.3, 3.57, 5.37, 5.75
(i) The maximum number of decimal places in the given decimals is 3. So, we convert each of the given decimals into like decimals having three decimal places by annexing zeros.
The decimals are: 6.600, 0.060, 0.600, 0.006, 6.660
Clearly, 6.660 > 6.600 > 0.600 > 0.060 > 0.006.
Hence, the given decimals in descending order are:
6.66 > 6.6 > 0.6 > 0.06 > 0.006
(ii) The maximum number of decimal places in the given decimals is 3. So, we convert each of the given decimals into like decimals having three decimal places by annexing zeros.
The decimals are: 3.300, 3.030, 0.330, 33.300, 0.303, 30.300
Clearly, 33.300 > 30.300 > 3.300 > 3.030 > 0.330 > 0.303.
Hence, the given decimals in descending order are:
33.3 > 30.3 > 3.3 > 3.03 > 0.33 > 0.303
(iii) The maximum number of decimal places in the given decimals is 2. So, we convert each of the given decimals into like decimals having two decimal places by annexing zeros.
The decimals are: 2.90, 3.60, 9.20, 6.30, 3.06, 6.03
Clearly, 9.20 > 6.30 > 6.03 > 3.60 > 3.06 > 2.90.
Hence, the given decimals in descending order are:
9.2 > 6.3 > 6.03 > 3.6 > 3.06 > 2.9
(iv) The maximum number of decimal places in the given decimals is 2. So, we have to convert each of the given decimals to have two places of decimal, by annexing zeros.
The decimals are: 77.70, 0.70, 7.70, 0.07, 7.07, 7.77
Clearly, 77.70 > 7.77 > 7.70 > 7.07 > 0.70 > 0.07.
Hence, the given decimals in descending order are:
77.7 > 7.77 > 7.7 > 7.07 > 0.7 > 0.07
(v) The maximum number of decimal places in the given decimals is 2. So, we have to convert each of the given decimals to have two places of decimal, by annexing zeros.
The decimals are: 7.35, 3.75, 5.30, 3.57, 5.37, 5.75
Clearly, 7.35 > 5.75 > 5.37 > 5.30 > 3.75 > 3.57.
Hence, the given decimals in descending order are:
7.35 > 5.75 > 5.37 > 5.3 > 3.75 > 3.57
Convert each of the following decimals into a fraction with lowest terms:
(i) 0.8
(ii) 0.06
(iii) 0.45
(iv) 0.64
(v) 5.4
(vi) 6.25
(vii) 8.125
(viii) 3.475
(i) Writing the decimal 0.8 as a fraction,
0.8 = $\frac{8}{10}=\frac{4}{5}$
Therefore, the required fraction is $\frac{4}{5}$ .
(ii) Writing the decimal 0.06 as a fraction,
0.06 = $\frac{6}{100}=\frac{3}{50}$
Therefore, the required fraction is $\frac{3}{50}$ .
(iii) Writing the decimal 0.45 as a fraction,
0.45 = $\frac{45}{100}=\frac{9}{20}$
Therefore, the required fraction is $\frac{9}{20}$ .
(iv) Writing the decimal 0.64 as a fraction,
0.64 = $\frac{64}{100}=\frac{16}{25}$
Therefore, the required fraction is $\frac{16}{25}$ .
(v) Writing the decimal 5.4 as a fraction,
5.4 = $\frac{54}{10}=\frac{27}{5}=5\frac{2}{5}$
Therefore, the required fraction is $5\frac{2}{5}$ .
(vi) Writing the decimal 6.25 as a fraction,
6.25 = $\frac{625}{100}=\frac{25}{4}=6\frac{1}{4}$
Therefore, the required fraction is $6\frac{1}{4}$ .
(vii) Writing the decimal 8.125 as a fraction,
8.125 = $\frac{8125}{1000}=\frac{65}{8}=8\frac{1}{8}$
Therefore, the required fraction is $8\frac{1}{8}$ .
(viii) Writing the decimal 3.475 as a fraction,
3.475 = $\frac{3475}{1000}=\frac{139}{40}=3\frac{19}{40}$
Therefore, the required fraction is $3\frac{19}{40}$ .
Convert each of the following fractions into decimals:
(i) $\frac{9}{10}$
(ii) $\frac{23}{10}$
(iii) $\frac{427}{10}$
(iv) $\frac{37}{100}$
(v) $\frac{107}{100}$
(vi) $\frac{1423}{100}$
(vii) $\frac{123}{1000}$
(viii) $\frac{2045}{1000}$
(i) Converting the fraction $\frac{9}{10}$ into a decimal,
$\frac{9}{10}=0.9$
Therefore, the decimal form is 0.9 .
(ii) Converting the fraction $\frac{23}{10}$ into a decimal,
$\frac{23}{10}=2\frac{3}{10}=2+\frac{3}{10}=2+0.3=2.3$
Therefore, the decimal form is 2.3 .
(iii) Converting the fraction $\frac{427}{10}$ into a decimal,
$\frac{427}{10}=42\frac{7}{10}=42+\frac{7}{10}=42+0.7=42.7$
Therefore, the decimal form is 42.7 .
(iv) Converting the fraction $\frac{37}{100}$ into a decimal,
$\frac{37}{100}=0.37$
Therefore, the decimal form is 0.37.
(v) Converting the fraction $\frac{107}{100}$ into a decimal,
$\frac{107}{100}=1\frac{7}{100}=1+\frac{7}{100}=1+0.07=1.07$
Therefore, the decimal form is 1.07 .
(vi) Converting the fraction $\frac{1423}{100}$ into a decimal,
$\frac{1423}{100}=14\frac{23}{100}=14+\frac{23}{100}=14+0.23=14.23$
Therefore, the decimal form is 14.23.
(vii) Converting the fraction $\frac{123}{1000}$ into a decimal,
$\frac{123}{1000}=0.123$
Therefore, the decimal form is 0.123 .
(viii) Converting the fraction $\frac{2045}{1000}$ into a decimal,
$\frac{2045}{1000}=2\frac{45}{1000}=2+\frac{45}{1000}=2+0.045=2.045$
Therefore, the decimal form is 2.045 .
Convert each of the following fractions into decimals:
(i) $\frac{3}{20}$
(ii) $\frac{7}{25}$
(iii) $\frac{9}{50}$
(iv) $\frac{1}{4}$
(v) $\frac{16}{125}$
(vi) $\frac{231}{250}$
(vii) $\frac{17}{500}$
(viii) $\frac{8}{250}$
(i) Converting the fraction $\frac{3}{20}$ into a decimal,
$\frac{3}{20}=\frac{3\times5}{20\times5}=\frac{15}{100}=0.15$
Therefore, the decimal form is 0.15.
(ii) Converting the fraction $\frac{7}{25}$ into a decimal,
$\frac{7}{25}=\frac{7\times4}{25\times4}=\frac{28}{100}=0.28$
Therefore, the decimal form is 0.28.
(iii) Converting the fraction $\frac{9}{50}$ into a decimal,
$\frac{9}{50}=\frac{9\times2}{50\times2}=\frac{18}{100}=0.18$
Therefore, the decimal form is 0.18.
(iv) Converting the fraction $\frac{1}{4}$ into a decimal,
$\frac{1}{4}=\frac{1\times25}{4\times25}=\frac{25}{100}=0.25$
Therefore, the decimal form is 0.25.
(v) Converting the fraction $\frac{16}{125}$ into a decimal,
$\frac{16}{125}=\frac{16\times8}{125\times8}=\frac{128}{1000}=0.128$
Therefore, the decimal form is 0.128.
(vi) Converting the fraction $\frac{231}{250}$ into a decimal,
$\frac{231}{250}=\frac{231\times4}{250\times4}=\frac{924}{1000}=0.924$
Therefore, the decimal form is 0.924.
(vii) Converting the fraction $\frac{17}{500}$ into a decimal,
$\frac{17}{500}=\frac{17\times2}{500\times2}=\frac{34}{1000}=0.034$
Therefore, the decimal form is 0.034.
(viii) Converting the fraction $\frac{8}{250}$ into a decimal,
$\frac{8}{250}=\frac{8\times4}{250\times4}=\frac{32}{1000}=0.032$
Therefore, the decimal form is 0.032.
Convert each of the following fractions into decimals:
(i) $5\frac{3}{4}$
(ii) $3\frac{1}{4}$
(iii) $6\frac{1}{5}$
(iv) $12\frac{4}{5}$
(v) $7\frac{3}{8}$
(vi) $2\frac{4}{25}$
(vii) $3\frac{7}{20}$
(viii) $4\frac{11}{20}$
(i) $5\frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{23}{4}$
By actual division, we have:
$$\begin{array}{l} \phantom{4)}{\space \phantom{2} 5.75} \\ 4\overline{\smash{\big)}\space 23.00} \\ \phantom{4)}\phantom{)}\underline{20} \\ \phantom{4)\space 2}30 \\ \phantom{4)\space 2}\underline{28} \\ \phantom{4)\space 28}20 \\ \phantom{4)\space 28}\underline{20} \\ \phantom{4)\space 28}\times \end{array}$$
$\therefore 5\frac{3}{4} = \frac{23}{4} = 5.75$
Therefore, the decimal form is 5.75.
(ii) $3\frac{1}{4}=\frac{3\times4 + 1}{4}=\frac{13}{4}$
By actual division, we have:
$$\begin{array}{l} \phantom{4)}{\space \phantom{2} 3.25} \\ 4\overline{\smash{\big)}\space 13.00} \\ \phantom{4)}\phantom{)}\underline{12} \\ \phantom{4)\space 2}10 \\ \phantom{4)\space 22}\underline{8} \\ \phantom{4)\space 28}20 \\ \phantom{4)\space 28}\underline{20} \\ \phantom{4)\space 28}\times \end{array}$$
Therefore, the decimal form is 3.25.
(iii) $6\frac{1}{5}=\frac{6\times5 + 1}{5}=\frac{31}{5}$
$$\begin{array}{l} \phantom{5)}{\space \phantom{2} 6.2} \\ 5\overline{\smash{\big)}\space 31.0} \\ \phantom{5)}\phantom{)}\underline{30} \\ \phantom{5)\space 2.}10 \\ \phantom{5)\space 2.}\underline{10} \\ \phantom{5)\space 28}\times \end{array}$$
Therefore, the decimal form is 6.2.
(iv) $12\frac{4}{5}=\frac{12 \times 5 + 4}{5}=\frac{64}{5}$
$$\begin{array}{l} \phantom{5)}{\space 12.8} \\ 5\overline{\smash{\big)}\space 64.0} \\ \phantom{5)}\phantom{)}\underline{5} \\ \phantom{5)\space .}14 \\ \phantom{5)\space .}\underline{10} \\ \phantom{5)\space 21}40 \\ \phantom{5)\space 55}\underline{40} \\ \phantom{5)\space 28.}\times \end{array}$$
Therefore, the decimal form is 12.8.
(v) $7\frac{3}{8}=\frac{7 \times 8 + 3}{8}=\frac{59}{8}$
$$\begin{array}{l} \phantom{8)}{\space \phantom{)} 7.375} \\ 8\overline{\smash{\big)}\space 59.000} \\ \phantom{8)}\phantom{)}\underline{56} \\ \phantom{8)\space )}030 \\ \phantom{8)\space )}\underline{\phantom{2}24} \\ \phantom{8)\space 22)}60 \\ \phantom{8)\space 55}\underline{\phantom{)}56} \\ \phantom{8)\space 222)}40 \\ \phantom{8)\space 55}\underline{\phantom{2)}40} \\ \phantom{8)\space 2831}\times \end{array}$$
Therefore, the decimal form is 7.375.
(vi) $2\frac{4}{25}=\frac{25 \times 2 + 4 }{25}=\frac{54}{25}$
$$\begin{array}{l} \phantom{25)}{\space \phantom{)} 2.16} \\ 25\overline{\smash{\big)}\space 54.00} \\ \phantom{25)}\phantom{)}\underline{50} \\ \phantom{25)\space ))}40 \\ \phantom{25)\space ))}\underline{25} \\ \phantom{25)\space ))}150 \\ \phantom{25)\space ))}\underline{150} \\ \phantom{25)\space 28)}\times \end{array}$$
Therefore, the decimal form is 2.16.
(vii) $3\frac{7}{20}=\frac{3 \times 20 + 7}{20}=\frac{67}{20}$
$$\begin{array}{l} \phantom{20)}{\space \phantom{)} 3.35} \\ 20\overline{\smash{\big)}\space 67.00} \\ \phantom{20)}\phantom{)}\underline{60} \\ \phantom{20)\space ))}70 \\ \phantom{20)\space ))}\underline{60} \\ \phantom{20)\space ))}100 \\ \phantom{20)\space ))}\underline{100} \\ \phantom{20)\space 28)}\times \end{array}$$
Therefore, the decimal form is 3.35.
(viii) $4\frac{11}{20}=\frac{4 \times 20 + 11}{20}=\frac{91}{20}$
$$\begin{array}{l} \phantom{20)}{\space \phantom{)} 4.55} \\ 20\overline{\smash{\big)}\space 91.00} \\ \phantom{20)}\phantom{)}\underline{80} \\ \phantom{20)\space )}110 \\ \phantom{20)\space )}\underline{100} \\ \phantom{20)\space )))}100 \\ \phantom{20)\space )))}\underline{100} \\ \phantom{20)\space 28))}\times \end{array}$$
Therefore, the decimal form is 4.55.
Add:
(i) 27.5, 8.93, 0.759, 9.6
(ii) 0.83, 8.07, 17.9, 294.678
(iii) 0.53, 7.07, 77.7, 0.835
(iv) 9.38, 3.895, 109.5, 72.87, 0.005
(v) 9.008, 27.689, 247.96, 39.8
(vi) 325.7, 98.079, 0.87, 236.68
(i) Converting the given decimals into like decimals, each having 3 places of decimal, we get :
27.500, 8.930, 0.759, 9.600
Writing these decimals in column form and adding, we get:
$$\begin{array}{r} \phantom{+}27.500 \\ 8.930 \\ 0.759 \\ +\space 9.600 \\ \hline 46.789 \end{array}$$
Therefore, the sum is 46.789.
(ii) Converting the given decimals into like decimals, each having 3 places of decimal, we get :
0.830, 8.070, 17.900, 294.678
Writing these decimals in column form and adding, we get:
$$\begin{array}{r} \phantom{+}0.830 \\ 8.070 \\ 17.900 \\ +\space 294.678 \\ \hline 321.478 \end{array}$$
Therefore, the sum is 321.478.
(iii) Converting the given decimals into like decimals, each having 3 places of decimal, we get :
0.530, 7.070, 77.700, 0.835
Writing these decimals in column form and adding, we get:
$$\begin{array}{r} \phantom{+}0.530 \\ 7.070 \\ 77.700 \\ +\space 0.835 \\ \hline 86.135 \end{array}$$
Therefore, the sum is 86.135.
(iv) Converting the given decimals into like decimals, each having 3 places of decimal, we get :
9.380, 3.895, 109.500, 72.870, 0.005
Writing these decimals in column form and adding, we get:
$$\begin{array}{r} \phantom{+}9.380 \\ 3.895 \\ 109.500 \\ 72.870 \\ +\space 0.005 \\ \hline 195.650 \end{array}$$
Therefore, the sum is 195.65.
(v) Converting the given decimals into like decimals, each having 3 places of decimal, we get :
9.008, 27.689, 247.960, 39.800
Writing these decimals in column form and adding, we get:
$$\begin{array}{r} \phantom{+}9.008 \\ 27.689 \\ 247.960 \\ +\space 39.800 \\ \hline 324.457 \end{array}$$
Therefore, the sum is 324.457.
(vi) Converting the given decimals into like decimals, each having 3 places of decimal, we get :
325.700, 98.079, 0.870, 236.680
Writing these decimals in column form and adding, we get:
$$\begin{array}{r} \phantom{+}325.700 \\ 98.079 \\ 0.870 \\ +\space 236.680 \\ \hline 661.329 \end{array}$$
Therefore, the sum is 661.329.
Find the difference:
(i) 17.05 - 9.78
(ii) 30.23 - 17.495
(iii) 107.5 - 58.69
(iv) 60 - 18.35
(v) 48.3 - 29.571
(vi) 100 - 72.745
(vii) 215.4 - 69.845
(viii) 1.5 - 0.703
(ix) 42 - 0.764
(i) Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}17.05 \\ -\space 9.78 \\ \hline 7.27 \end{array}$$
Therefore, the difference is 7.27.
(ii) Converting the given decimals into like decimals, each having 3 places of decimal, we get 30.230 and 17.495.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}30.230 \\ -\space 17.495 \\ \hline 12.735 \end{array}$$
Therefore, the difference is 12.735.
(iii) Converting the given decimals into like decimals, each having 2 places of decimal, we get 107.50 and 58.69.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}107.50 \\ -\space 58.69 \\ \hline 48.81 \end{array}$$
Therefore, the difference is 48.81 .
(iv) Converting the given decimals into like decimals, each having 2 places of decimal, we get 60.00 and 18.35.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}60.00 \\ - \space 18.35 \\ \hline 41.65 \end{array}$$
Therefore, the difference is 41.65 .
(v) Converting the given decimals into like decimals, each having 3 places of decimal, we get 48.300 and 29.571.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}48.300 \\ -\space 29.571 \\ \hline 18.729 \end{array}$$
Therefore, the difference is 18.729
(vi) Converting the given decimals into like decimals, each having 3 places of decimal, we get 100.000 and 72.745.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}100.000 \\ -\space 72.745 \\ \hline 27.255 \end{array}$$
Therefore, the difference is 27.255.
(vii) Converting the given decimals into like decimals, each having 3 places of decimal, we get 215.400 and 69.845.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}215.400 \\ -\space 69.845 \\ \hline 145.555 \end{array}$$
Therefore, the difference is 145.555.
(viii) Converting the given decimals into like decimals, each having 3 places of decimal, we get 1.500 and 0.703.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}1.500 \\ -\space 0.703 \\ \hline 0.797 \end{array}$$
Therefore, the difference is 0.797.
(ix) Converting the given decimals into like decimals, each having 3 places of decimal, we get 42.000 and 0.764.
Writing the decimals in column form and subtracting, we get :
$$\begin{array}{r} \phantom{+}42.000 \\ -\space 0.764 \\ \hline 41.236 \end{array}$$
Therefore, the difference is 41.236.
Simplify:
(i) 74.8 + 68.79 - 47.609 - 7.08
(ii) 68.3 - 102.735 + 217.96 - 37.7
(iii) 203.5 - 43.76 - 9.89 - 13.086
(iv) 77.7 - 7.555 - 5.77
(i) Writing each of the given numbers with three decimal places, we get:
Given expression = 74.800 + 68.790 - 47.609 - 7.080
$\phantom{74.800 + 68.790-}$= (74.800 + 68.790) - (47.609 + 7.080)
Now,
$$\begin{array}{r} \phantom{+}74.800 \\ +\space 68.790 \\ \hline 143.590 \end{array} \qquad \text{and} \qquad \begin{array}{r} \phantom{+}47.609 \\ +\space 7.080 \\ \hline 54.689 \end{array}$$
So,
$$\begin{array}{r} \phantom{+}143.590 \\ -\space 54.689 \\ \hline 88.901 \end{array}$$
Therefore, 74.8 + 68.79 - 47.609 - 7.08 = 88.901.
(ii) Writing each of the given numbers with three decimal places, we get:
Given expression = 68.300 - 102.735 + 217.960 - 37.700
$\phantom{68.300 + 217.960-}$= (68.300 + 217.960) - (102.735 + 37.700)
Now,
$$\begin{array}{r} \phantom{+}68.300 \\ +\space 217.960 \\ \hline 286.260 \end{array} \qquad \text{and} \qquad \begin{array}{r} \phantom{+}102.735 \\ +\space 37.700 \\ \hline 140.435 \end{array}$$
So,
$$\begin{array}{r} \phantom{+}286.260 \\ -\space 140.435 \\ \hline 145.825 \end{array}$$
Therefore, 68.3 - 102.735 + 217.96 - 37.7 = 145.825.
(iii) Writing each of the given numbers with three decimal places, we get:
Given expression = 203.500 - 43.760 - 9.890 - 13.086
$\phantom{203.500 + 217.960}$= 203.500 - ( 43.760 + 9.890 + 13.086)
Now,
$$\begin{array}{r} \phantom{+}43.760 \\ 9.890 \\ +\space 13.086 \\ \hline 66.736 \end{array}$$
So,
$$\begin{array}{r} \phantom{+}203.500 \\ -\space 66.736 \\ \hline 136.764 \end{array}$$
Therefore, 203.5 - 43.76 - 9.89 - 13.086 = 136.764.
(iv) Writing each of the given numbers with three decimal places, we get:
Given expression = 77.700 - 7.555 - 5.770
$\phantom{203.500 + 217.960}$= 77.700 - ( 7.555 + 5.770)
Now,
$$\begin{array}{r} \phantom{+}7.555 \\ +\space 5.770 \\ \hline 13.325 \end{array}$$
So,
$$\begin{array}{r} \phantom{+}77.700 \\ -\space 13.325 \\ \hline 64.375 \end{array}$$
Therefore, 77.7 - 7.555 - 5.77 = 64.375.
What is to be added to 73.6 to get 91.03 ?
Let the number be x. Then,
73.6 + x = 91.03
Solving for x,
x = 91.03 - 73.6
Rewriting the numbers with two decimal places,
x = 91.03 - 73.60
Writing in column form and subtracting, we get:
$$\begin{array}{r} \phantom{+}91.03 \\ -\space 73.60 \\ \hline 17.43 \end{array}$$
Therefore, x = 17.43.
What is to be subtracted from 6.1 to get 0.785 ?
Let the number to be subtracted from 6.1 be x. Then,
6.1 − x = 0.785
Solving for x,
x = 6.1 − 0.785
Rewriting the numbers with three decimal places,
x = 6.100 − 0.785
Writing in column form and subtracting, we get:
$$\begin{array}{r} \phantom{+}6.100 \\ -\space 0.785 \\ \hline 5.315 \end{array}$$
Therefore, x = 5.315.
By how much should 32.987 be increased to get 60 ?
Let the required increase be x. Then,
32.987 + x = 60
Solving for x,
x = 60 − 32.987
Rewriting the numbers with three decimal places,
x = 60.000 − 32.987
Writing in column form and subtracting, we get:
$$\begin{array}{r} \phantom{+}60.000 \\ -\space 32.987 \\ \hline 27.013 \end{array}$$
Therefore, x = 27.013.
By how much should 72.5 be decreased to get 18.76 ?
Let the required decrease be x. Then,
72.5 − x = 18.76
Solving for x,
x = 72.5 − 18.76
Rewriting the numbers with two decimal places,
x = 72.50 − 18.76
Writing in column form and subtracting, we get:
$$\begin{array}{r} \phantom{+}72.50 \\ -\space 18.76 \\ \hline 53.74 \end{array}$$
Therefore, x = 53.74.
The sum of two numbers is 34.02. If one of the numbers is 16.268, find the other.
Let the other number be x. Then,
x + 16.268 = 34.02
Solving for x,
x = 34.02 − 16.268
Rewriting the numbers with three decimal places,
x = 34.020 − 16.268
Writing in column form and subtracting, we get:
$$\begin{array}{r} \phantom{+}34.020 \\ -\space 16.268 \\ \hline 17.752 \end{array}$$
Therefore, x = 17.752.
Sajjal bought a geometry box for ₹ 139.75 and an exercise book for ₹ 59.60 from a book shop. He gave a 500-rupee note to the shopkeeper. What amount did he get back?
Cost of geometry box = ₹ 139.75
Cost of exercise book = ₹ 59.60
The total cost is,
$$\begin{array}{r} \phantom{+}139.75 \\ +\space 59.60 \\ \hline 199.35 \end{array}$$
Money given to the shopkeeper = ₹ 500
Amount returned = 500 − 199.35
Rewriting with two decimal places,
Amount returned = 500.00 − 199.35
Writing in column form and subtracting, we get:
$$\begin{array}{r} \phantom{+}500.00 \\ -\space 199.35 \\ \hline 300.65 \end{array}$$
Therefore, the amount received back is ₹ 300.65.
Rajan purchased a geometry box for ₹ 136.75, a colour box for ₹ 48.80 and a register for ₹ 64.50. What amount did he pay to the shopkeeper?
Cost of the geometry box = ₹ 136.75
Cost of the colour box = ₹ 48.80
Cost of the register = ₹ 64.50
Total amount = 136.75 + 48.80 + 64.50
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}136.75 \\ 48.80 \\ +\space 64.50 \\ \hline 250.05 \end{array}$$
Hence, the total amount paid is ₹ 250.05.
Sakshi bought 3 m 28 cm cloth for her shirt and 2 m 7 cm for her trousers. What is the total length of cloth bought by her?
Length of cloth for shirt = 3 m 28 cm
= 3 m + $\frac{28}{100}$ m = 3 m + 0.28 m = 3.28 m
Length of cloth for trousers = 2 m 7 cm
= 2 m + $\frac{7}{100}$ m = 2 m + 0.07 m = 2.07 m
Total length of the cloth = 3.28 + 2.07
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}3.28 \\ +\space 2.07 \\ \hline 5.35 \end{array}$$
Hence, the total length of the cloth bought by Sakshi is 5.35 m or 5 m 35 cm.
A bag contains 95 kg 80 g of rice and the mass of the empty bag is 860 g. What is the weight of the bag filled with rice?
Mass of rice = 95 kg 80 g
= 95 kg + $\frac{80}{1000}$ kg = 95 kg + 0.080 kg = 95.080 kg
Mass of empty bag = 860 g = $\frac{860}{1000}$ = 0.860 kg
Total weight of the bag filled with rice = 95.080 + 0.860
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}95.080 \\ +\space 0.860 \\ \hline 95.940 \end{array}$$
Hence, the total weight of the bag filled with rice is 95.940 kg or 95 kg 940 g.
Distance between Delhi and Meerut is 85 km 850 m and the distance between Meerut and Muzaffarnagar is 56 km 85 m. What is the distance between Delhi and Muzaffarnagar?
Distance between Delhi and Meerut = 85 km 850 m
= 85 km + $\frac{850}{1000}$ = 85 km + 0.850 = 85.850 km
Distance between Meerut and Muzaffarnagar = 56 km 85 m
= 56 km + $\frac{85}{1000}$ = 56 km + 0.085= 56.085 km
The total distance between Delhi and Muzaffarnagar = 85.850 + 56.085
$$\begin{array}{r} \phantom{+}85.850 \\ +\space 56.085 \\ \hline 141.935 \end{array}$$
Hence, the total distance between Delhi and Muzaffarnagar is 141.935 km or 141 km 935 m.
Divya purchased a book worth ₹ 256.85 and a set of note-books worth ₹ 546.70. She gave a ₹ 2000 note to the shopkeeper. How much money did she get back?
Cost of the book = ₹ 256.85
Cost of note-books = ₹ 546.70
Total cost = 256.85 + 546.70
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}256.85 \\ +\space 546.70 \\ \hline 803.55 \end{array}$$
Money given to the shopkeeper = ₹ 2000
Amount returned to Divya = 2000.00 - 803.55
Writing in column form and subtracting:
$$\begin{array}{r} \phantom{+}2000.00 \\ -\space 803.55 \\ \hline 1196.45 \end{array}$$
Hence, the total amount returned by the shopkeeper is ₹ 1196.45.
The weight of a gas cylinder filled with gas is 32 kg 200 g. If the weight of the gas contained in it is 17 kg 80 g, find the weight of the empty cylinder.
Weight of the filled cylinder = 32 kg 200 g
= 32 kg + $\frac{200}{1000}$ kg = 32 kg + 0.200 kg = 32.200 kg
Weight of gas contained in the cylinder = 17 kg 80 g
= 17 kg + $\frac{80}{1000}$ kg = 17 kg + 0.080 kg = 17.080 kg
Weight of empty cylinder = 32.200 − 17.080
Writing in column form and subtracting:
$$\begin{array}{r} \phantom{+}32.200 \\ -\space 17.080 \\ \hline 15.120 \end{array}$$
Hence, weight of empty cylinder is 15.120 kg or 15 kg 120 g.
Stuti went to the market with ₹ 3000 in cash. Out of this money, she purchased one frock, one toy and one bag costing ₹ 675.85, ₹ 318 and ₹ 1972.75 respectively. How much money is left with her?
Initial amount with Stuti = ₹ 3000
Total amount spent:
Cost of the frock = ₹ 675.85
Cost of the toy = ₹ 318.00
Cost of the bag = ₹ 1972.75
Total amount spent = 675.85 + 318.00 + 1972.75
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}675.85 \\ 318.00 \\ +\space 1972.75 \\ \hline 2966.60 \end{array}$$
Money left = 3000.00 - 2966.60
Writing in column form and subtracting:
$$\begin{array}{r} \phantom{+}3000.00 \\ -\space 2966.60 \\ \hline 33.40 \end{array}$$
Hence, Stuti has ₹ 33.40 left with her.
The total weight of a bag containing 25 kg 750 g of potatoes and 18 kg 80 g of melon is 44 kg 200 g. How much is the weight of the empty bag?
Weight of potatoes = 25 kg 750 g
= 25 kg + $\frac{750}{1000}$ kg = 25 kg + 0.750 kg= 25.750 kg
Weight of melon = 18 kg 80 g
= 18 kg + $\frac{80}{1000}$ kg = 18 kg + 0.080 kg = 18.080 kg
Total weight of the bag = 44 kg 200 g
= 44 kg + $\frac{200}{1000}$ kg = 44 kg + 0.200 kg = 44.200 kg
Weight of empty bag = 44.200 − (25.750 + 18.080)
$$\begin{array}{r} \phantom{+}25.750 \\ +\space 18.080 \\ \hline 43.830 \end{array} \qquad \text{and} \qquad \begin{array}{r} \phantom{+}44.200 \\ -\space 43.830 \\ \hline 0.370 \end{array}$$
Hence, the weight of the empty bag is 0.370 kg or 370 g.
If the school bags of Divya and Rahul weigh 8 kg 60 g and 6 kg 275 g respectively, whose bag is heavier and by how much?
Weight of Divya’s bag = 8 kg 60 g
= 8 kg + $\frac{60}{1000}$ kg = 8 kg + 0.060 kg = 8.060 kg
Weight of Rahul’s bag = 6 kg 275 g
= 6 kg + $\frac{275}{1000}$ kg = 6 kg + 0.275 kg = 6.275 kg
Since 8.060 > 6.275, Divya's bag is heavier than Rahul's bag.
The difference in weight = 8.060 - 6.275
Writing in column form and subtracting:
$$\begin{array}{r} \phantom{+}8.060 \\ -\space 6.275 \\ \hline 1.785 \end{array}$$
Divya's bag is heavier by 1.785 kg or 1 kg 785 g.
The distance between Naman's office and his house is 19 km. He covers 14 km 65 m by scooter, 3 km 75 m by bus and the rest on foot. How much distance does he cover by walking?
Total distance = 19 km
Distance covered by scooter = 14 km 65 m
= 14 km + $\frac{65}{1000}$ km = 14 km + 0.065 km = 14.065 km
Distance covered by bus = 3 km 75 m
= 3 km + $\frac{75}{1000}$ km = 3 km + 0.075 km= 3.075 km
Total distance covered = 14.065 + 3.075
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}14.065 \\ +\space 3.075 \\ \hline 17.140 \end{array}$$
So, the total distance covered = 17.140 km
Distance covered on foot = 19.000 - 17.140
Writing in column form and subtracting:
$$\begin{array}{r} \phantom{+}19.000 \\ -\space 17.140 \\ \hline 1.860 \end{array}$$
The distance covered by walking is 1.860 km or 1 km 860 m.
There was an electric wire of length 100 m. Out of it, three pieces of length 26 m 85 cm, 3 m 18 cm, and 18 m 70 cm were cut off. What is the length of the remaining wire?
Total length of the wire = 100 m
Length of the first piece = 26 m 85 cm
= 26 m + $\frac{85}{100}$ m = 26 m + 0.85 m = 26.85 m
Length of the second piece = 3 m 18 cm
= 3 m + $\frac{18}{100}$ m = 3 m + 0.18 m = 3.18 m
Length of the third piece = 18 m 70 cm
= 18 m + $\frac{70}{100}$ m = 18 m + 0.70 m = 18.70 m
Total length cut off = 26.85 + 3.18 + 18.70
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}26.85 \\ 3.18 \\ +\space 18.70 \\ \hline 48.73 \end{array}$$
Total length cut off = 48.73 m
Length of remaining wire = 100.00 - 48.73
$$\begin{array}{r} \phantom{+}100.00 \\ -\space 48.73 \\ \hline 51.27 \end{array}$$
The remaining wire is 51.27 m or 51 m 27 cm long.
A bag contained 98 kg 300 g of wheat. There was a consumption of 36 kg 450 g, 28 kg 360 g and 32 kg 880 g during three months. How much wheat remains in the bag?
Total amount of wheat present in the bag = 98 kg 300 g
= 98 kg + $\frac{300}{1000}$ kg = 98 kg + 0.300 kg = 98.300 kg
Consumption in month 1 = 36 kg 450 g
= 36 kg + $\frac{450}{1000}$ kg = 36 kg + 0.450 kg = 36.450 kg
Consumption in month 2 = 28 kg 360 g
= 28 kg + $\frac{360}{1000}$ kg = 28 kg + 0.360 kg = 28.360 kg
Consumption in month 3 = 32 kg 880 g
= 32 kg + $\frac{880}{1000}$ kg = 32 kg + 0.880 kg = 32.880 kg
Total consumption during the three months = (36.450 + 28.360 + 32.880 ) kg
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}36.450 \\ 28.360 \\ +\space 32.880 \\ \hline 97.690 \end{array}$$
Total wheat consumed in three months = 97.690 kg
Amount of wheat remaining in the bag = 98.300 - 97.690
$$\begin{array}{r} \phantom{+}98.300 \\ -\space 97.690 \\ \hline 0.610 \end{array}$$
Therefore 0.610 kg or 610 g of wheat is remaining in the bag.
Out of 260 litres of milk, a milkman sold 36 l 500 ml, 75 l 750 ml, 68 l 400 ml and 42 l 850 ml. How much milk is left with him?
Initial amount of milk = 260 l
We know that,
36 l 500 ml = 36 l + $\frac{500}{1000}$ l = 36 l + 0.500 l = 36.500 l
75 l 750 ml = 75 l + $\frac{750}{1000}$ l = 75 l + 0.750 l = 75.750 l
68 l 400 ml = 68 l + $\frac{400}{1000}$ l = 68 l + 0.400 l = 68.400 l
42 l 850 ml = 42 l + $\frac{850}{1000}$ l = 42 l + 0.850 l = 42.850 l
Total amount of milk sold = (36.500 + 75.750 + 68.400 + 42.850) l
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}36.500 \\ 75.750 \\ 68.400 \\ +\space 42.850 \\ \hline 223.500 \end{array}$$
Total amount of milk sold is 223.500 l.
Milk remaining = (260.000 - 223.500) l
Writing in column form and subtracting,
$$\begin{array}{r} \phantom{+}260.000 \\ -\space 223.500 \\ \hline 36.500 \end{array}$$
The milkman has 36.500 l or 36 l 500 ml of milk left.
The place value of 3 in 5.136 is
The number is 5.136. The digit 3 is in the hundredths place.
So, its place value is $\frac{3}{100}$.
Hence, Option 3 is the correct option.
The place value of 4 in 3.046 is
The number is 3.046. The digit 4 is in the hundredths place.
So, its place value is $\frac{4}{100}$.
Hence, Option 4 is the correct option.
$3\frac{7}{10} = ?$
We have,
$3 \frac{7}{10}=3+\frac{7}{10}=3+0.7 = 3.7$
Hence, Option 1 is the correct option.
0.125 when expressed as a fraction in lowest terms is
The given decimal is 0.125.
Writing the decimal as a fraction,
0.125 = $\frac{125}{1000} = \frac{1}{8}$
Hence, Option 2 is the correct option.
8 rupees 5 paise can be expressed as
We know that 1 rupee = 100 paise
So, 5 paise = $\frac{5}{100} = 0.05$ rupees
So 8 rupees 5 paise = 8 + 0.05 = 8.05 rupees
Hence, Option 3 is the correct option.
1 + 0.1 + 0.01 = ?
The maximum number of decimal places in the given decimals is 2. So, we have to convert each of the given decimals to have two places of decimal, by annexing zeros.
So the expression is, 1.00 + 0.10 + 0.01
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}1.00 \\ 0.10 \\ +\space 0.01 \\ \hline 1.11 \end{array}$$
So the sum is 1.11.
Hence, Option 2 is the correct option.
$6\frac{19}{1000} = ?$
We have,
$6\frac{19}{1000} =6+\frac{19}{1000}=6+0.019=6.019$
So the decimal form is 6.019.
Hence, Option 3 is the correct option.
6.9, 5.4, 3.5 and 7.2 are
The decimals 6.9, 5.4, 3.5 and 7.2 have one decimal place each. So, they are like decimals.
Hence, Option 1 is the correct option.
Which is greater, 5.08 or 5.8?
Rewriting 5.08 and 5.8 as like decimals, we have 5.08 and 5.80.
Comparing the tenths place, we know that 8 > 0. So, 5.80 > 5.08.
Hence, Option 2 is the correct option.
4.17 + 3.06 + 5.135 = ?
Rewriting 4.17 + 3.06 + 5.135 as like decimals,
4.170 + 3.060 + 5.135
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}4.170 \\ 3.060 \\ +\space 5.135 \\ \hline 12.365 \end{array}$$
So the sum is 12.365.
Hence, Option 2 is the correct option.
5 tenths, when expressed as a decimal, is
5 tenths means: $\frac{5}{10}$
Converting into decimal,
$\frac{5}{10} = 0.5$
Hence, 5 tenths as a decimal is 0.5.
Hence, Option 1 is the correct option.
0.3 + 0.33 = ?
Rewriting 0.3 + 0.33 as like decimals: 0.30 + 0.33
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}0.30 \\ +\space 0.33 \\ \hline 0.63 \end{array}$$
So the sum is 0.63.
Hence, Option 3 is the correct option.
6 km 225 m + 3 km 75 m = ?
We have,
6 km 225 m = 6 km + $\frac{225}{1000}$ km = 6 km + 0.225 km = 6.225 km
3 km 75 m = 3 km + $\frac{75}{1000}$ km = 3 km + 0.075 km = 3.075 km
So,
6 km 225 m + 3 km 75 m = (6.225 + 3.075) km
So the correct representation is (6.225 + 3.075) km.
Hence, Option 2 is the correct option.
Fill in the blanks:
(i) 6 hundredths in decimal form is ............... .
(ii) $\frac{6}{25}$ in decimal form is ............... .
(iii) 2 m 15 cm + 6 m 5 cm = ............... metres.
(iv) 15P + 5P = ₹ ............... .
(v) 15 km + 75 m = ............... .
(vi) (2 cm - 5 mm) = ............... cm.
(i) 6 hundredths is represented as $\frac{6}{100}$
So, $\frac{6}{100}=0.06$
6 hundredths in decimal form is 0.06.
(ii) We have,
$\frac{6}{25} = \frac{6 \times 4}{25 \times 4} = \frac{24}{100} = 0.24$
$\frac{6}{25}$ in decimal form is 0.24.
(iii) We know that,
2 m 15 cm = 2 m + $\frac{15}{100}$ = 2 m + 0.15 = 2.15 m
6 m 5 cm = 6 m + $\frac{5}{100}$ = 6 m + 0.05 = 6.05 m
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}2.15 \\ +\space 6.05 \\ \hline 8.20 \end{array}$$
2 m 15 cm + 6 m 5 cm = 8.20 metres.
(iv) We have,
15 P = $\frac{15}{100} = ₹ 0.15$
5 P = $\frac{5}{100} = ₹ 0.05$
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}0.15 \\ +\space 0.05 \\ \hline 0.20 \end{array}$$
So, 15 P + 5 P = ₹ ( 0.15 + 0.05 ) = ₹ 0.20.
(v) We know that, 75 m = $\frac{75}{1000}$ km = 0.075 km.
15 km + 75 m = ( 15.000 + 0.075 ) km
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}15.000 \\ +\space 0.075 \\ \hline 15.075 \end{array}$$
So, 15 km + 75 m = 15.075 km.
(vi) We have, 5 mm = $\frac{5}{10}$ cm = 0.5 cm.
(2 cm - 5 mm) = (2.0 - 0.5) cm
Writing in column form and subtracting:
$$\begin{array}{r} \phantom{+}2.0 \\ -\space 0.5 \\ \hline 1.5 \end{array}$$
So, (2 cm - 5 mm) = 1.5 cm.
Write (T) for true and (F) for false for each of the statements given below:
(i) 3 m 5 cm = 3.5 m
(ii) 16 km 30 m = 16.30 km
(iii) ₹ 8 + 6 P = ₹ (8.60)
(iv) 0.03 = 3 hundredths
(v) 7 kg 80 g = 7.8 kg
(vi) 0.1 + 0.01 + 0.001 = 0.111
(i) F
Reason —
3 m 5 cm = 3 m + $\frac{5}{100}$ m = 3 m + 0.05 m = 3.05 m, and not 3.5 m.
(ii) F
Reason —
16 km 30 m = 16 km + $\frac{30}{1000}$ km = 16 km + 0.030 km = 16.030 km, not 16.30 km.
(iii) F
Reason — Here, 6 P = $\frac{6}{100} ₹= ₹ 0.06$.
So, ₹ 8 + 6 P = ₹ (8 + 0.06) = ₹ 8.06.
(iv) T
Reason —
0.03 = $\frac{3}{100}$
So, 0.03 is 3 hundredths.
(v) F
Reason — We have, 80 g = $\frac{80}{1000}$ kg = 0.08 kg.
So, 7 kg 80 g =(7 + 0.08) kg = 7.08 kg
(vi) T
Reason — Rewriting the decimals to be like decimals,
0.1 + 0.01 + 0.001 = 0.100 + 0.010 + 0.001
Writing in column form and adding:
$$\begin{array}{r} \phantom{+}0.100 \\ 0.010 \\ +\space 0.001 \\ \hline 0.111 \end{array}$$
So the sum is 0.111.
Assertion. The place value of the digit 4 in 2.147 is $\frac{4}{100}$
Reason. The place value of a digit at hundredths place is 10 times the same digit at the tenths place.
In the number 2.147, the digit 4 is in the hundredths place. So, its place value is $\frac{4}{100}$.
So the Assertion (A) is true.
The place value of a digit at the hundredths place is actually $\frac{1}{10}$ of the value it would have at the tenths place, not 10 times.
So the Reason (R) is false.
Option 3 is the correct option.
Assertion. The decimal numbers 2.5, 2.05, 2.005 and 2.0005 are equivalent.
Reason. Any number of zeros put at the end of a decimal number does not change its value.
The decimal numbers 2.5, 2.05, 2.005 and 2.0005 are not equivalent because the zero is being placed between the decimal point and the digit $5$ which changes its place value from tenths to hundredths, and so on.
Therefore the Assertion (A) is false.
Adding zeros at the end of a decimal number does not change its value. For example, 2.5 = 2.50, the value does not change.
So the Reason (R) is true.
Option 4 is the correct option.
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