1 mole of CO2 occupies 24 dm3 at room temperature and pressure. Calculate the following:
(a) The mass of 6 litres of CO2.
(b) The volume occupied by 60 g of CO2.
[Atomic weight: C=12, O=16]
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Given:
1 mole of CO2 occupies 24 dm3 (24 L) at room temperature and pressure
Gram molecular mass of CO2 = 12 + 2 x 16 = 44 g
(a) 24 litres of CO2 weighs = 44 g (at room temperature & pressure)
∴ Mass of 6 litres of CO2 = $\frac{44}{24}$ x 6 = 11 g (at room temperature & pressure)
Hence, mass of 6 litres of CO2 at room temperature & pressure is 11 g.
(b) Volume occupied by 44 g of CO2 = 24 litres (at room temperature & pressure)
∴ Volume occupied by 60 g of CO2 = $\frac{24}{44}$ x 60 ≈ 32.72 litres (at room temperature & pressure)
Hence, volume occupied by 60 g of CO2 ≈ 32.72 litres (at room temperature & pressure)