Two metallic blocks P and Q having masses in ratio 2 : 1 are supplied with the same amount of heat. If their temperatures rise by same degree, compare their…

Let mass of block P = m_p and mass of block Q = m_Q

Given,

$\frac{m_p}{m_Q}$ = $\frac{2}{1}$

Q = m x s x ∆t

Since, heat supplied (∆Q) and rise in temperature (∆t) is same for both block P and Q,

Therefore,

$$\begin{aligned}m_p \times s_p \times ∆t = m_Q \times s_Q \times ∆t \\[0.5em] m_p \times s_p = m_Q \times s_Q \\[0.5em] \frac{s_p}{s_Q} = \frac{m_Q}{m_p} = \frac{1}{2}\end{aligned}$$

Therefore, s_P : s_Q = 1 : 2