1(viii)
Matrix $$A = \begin{bmatrix} -1 & 2 \\ 3 & 0 \end{bmatrix}$$ and the Matrix $$mA = \begin{bmatrix} 3 & -6 \\ -9 & 0 \end{bmatrix}$$. The value of $m$ is:
- (a)$-\frac{1}{3}$
- (b)– 3
- (c)$\frac{1}{3}$
- (d)3
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Given,
$$mA = m\begin{bmatrix} -1 & 2 \\ 3 & 0 \end{bmatrix} = \begin{bmatrix} -m & 2m \\ 3m & 0 \end{bmatrix}$$
Comparing this with the given matrix $$\begin{bmatrix} 3 & -6 \\ -9 & 0 \end{bmatrix}$$,
$$\begin{aligned}\Rightarrow -m = 3\\[1em] \Rightarrow m = -3.\end{aligned}$$
Hence, option 2 is the correct option.