If $$A = \begin{bmatrix*}[r] 3 & -2 \end{bmatrix*} ext{ and } B = \begin{bmatrix*}[r] -1 & 4 \ 2 & 0 \end{bmatrix*}$$

Question

If $$A = \begin{bmatrix*}[r] 3 & -2 \end{bmatrix*} \text{ and } B = \begin{bmatrix*}[r] -1 & 4 \\ 2 & 0 \end{bmatrix*}$$

Assertion (A) : Product AB of the two matrices A and B is possible

Reason (R) : Number of columns of matrix A is equal to number of rows in matrix B.

Accepted Answer

Order of matrix A = 1 × 2

Order of matrix B = 2 × 2

Since, no. of columns in A is equal to number of rows in B.

∴ AB is possible.

∴ Assertion (A) and Reason (R) is true.

Hence, Option 3 is the correct option.

If $$A = \begin{bmatrix*}[r] 3 & -2 \end{bmatrix*} \text{ and } B = \begin{bmatrix*}[r] -1 & 4 \\ 2 & 0 \end{bmatrix*}$$