1(i)
The given quadratic equation 3x2 + $\sqrt{7}$ x + 2 = 0 has:
- (a)two equal real roots.
- (b)two distinct real roots.
- (c)more than two real roots.
- (d)no real roots.
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Comparing the given quadratic equation with ax2 + bx + c = 0, we get :
a = 3, b = $\sqrt{7}$ and c = 2
Discriminant = b2 - 4ac
= $(\sqrt{7})^2$ - 4 x 3 x 2
= 7 - 24
= -17.
Since, D < 0, there are no real roots.
Hence, option 4 is the correct option.