Study the table given below. Use only the letters given in the table to answer the questions. Do not identify the elements.

ICSE Class 10 Chemistry PYQ · 2025 Paper · Section B

4(iv)Written · 2025 · Section B · 2025 Paper

Study the table given below. Use only the letters given in the table to answer the questions. Do not identify the elements.

IAIIAIIIAIVAVAVIAVIIA0
   E J Q
 L  G   
 MD   P 
 N      

(a) State the valency of element ‘G’.

(b) Which element can exhibit catenation?

(c) Write the formula of the compound formed between ‘M’ and ‘P’.

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(a) Element G

Reason — Element G belongs to group VA (group 15). Group 15 elements have 5 valence electrons in their outermost shell they can gain 3 electrons to complete the octet hence, the valency will be 3.

(b) Element E

Reason — Catenation (ability to form long chains of its own atoms) is strongest in the group IVA (14) element shown, i.e., E.

(c) Element m

Reason — M is in group IIA they have 2 valence electrons and forms M2+ and P is in group VIIA have 7 valence electrons and forms P-, so one molecule of M combines with two molecules of P. Hence, the neutral formula is MP2.

$$\begin{aligned}\text{M}^{2+} \space \text{P}^{1-} \\[1em] \overset{\phantom{2}{2}}{\text{M}} \space {\swarrow}\mathllap{\searrow} \space \overset{1}{\text{P}} \Rightarrow \underset{\phantom{1}{1}}{\text{M}} \space {\swarrow}\mathllap{\searrow} \underset{\phantom{2}{2}}{\text{P}} \\[1em] \text{M}\text{P}_2\end{aligned}$$

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