1(iv)
An organic compound has a vapour density of 22. The molecular formula of the organic compound is: [Atomic weight: C = 12, H = 1]
- (a)CH4
- (b)C2H4
- (c)C2H6
- (d)C3H8
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C3H8
Reason
Given,
Vapour density of organic compound = 22
Molecular weight = 2 x V.D. = 2 x 22 = 44
| Compound | Molecular mass |
|---|---|
| 1. CH4 | 16 |
| 2. C2H4 | 28 |
| 3. C2H6 | 30 |
| 4. C3H8 | 44 |
Hence, C3H8 is a organic compound that has the molecular mass of 44.