5(c)
(i) State the volume occupied by 40 gm of methane at STP, if its vapour density (V.D.) is 8.
(ii) Calculate the number of moles present in 160 gm of NaOH.
[Atomic Mass: Na = 23, H= 1, O= 16]
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(i) Gram molecular mass of methane = V.D. x 2 = 8 x 2 = 16 g
16 g of methane occupies 22.4 lit.
∴ 40 g of methane will occupy = $\frac{22.4}{16}$ x 40 = 56 lits.
(ii) Gram molecular mass of NaOH = 23 + 16 + 1 = 40 g
40 g of NaOH = 1 mole
∴ 160 g of NaOH = $\frac{160}{40}$ = 4 moles.